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For a certain reaction, ΔG° = 87 kJ/mol, ΔH° = 100 kJ/mol at STP. At what temperature, in K, is the reaction at equilibrium, assuming that ΔS° and ΔH° are temperature-independent? Round the answer to two significant digits. Group of answer choices 1,700 K 1,900 K 2,100 K 2,300 K None of the above

For a certain reaction, ΔG° = 87 kJ/mol, ΔH° = 100 kJ/mol at STP. At what temperature, in K, is the reaction at equilibrium, assuming that ΔS° and ΔH° are temperature-independent? Round the answer to two significant digits. Group of answer choices 1,700 K 1,900 K 2,100 K 2,300 K None of the above

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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For a certain reaction, ΔG° = 87 kJ/mol, ΔH° = 100 kJ/mol at STP. At what temperature, in K, is the reaction at equilibrium, assuming that ΔS° and ΔH° are temperature-independent?

Round the answer to two significant digits.

Group of answer choices
1,700 K
1,900 K
2,100 K
2,300 K
None of the above
Expert Solution
Step 1

At, STP temperature , T=273KWe know that, ∆G° = ∆H° - T∆S°Given that,     ∆G° =87 KJ/mol     ∆H° =100 KJ/mol         T = 273KPutting these values in above equation-       87 = 100- 273×∆S° ⇒   ∆S° = 0.0476 KJ/mol .K  ⇒ ∆S° = 47.6 J/mol K

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