For a certain distribution of 100 items the three moments about the mean 50 are found to be 144, 4, 26000. It was found at the time of checking that 55 and 49 were wrongly written as 56 and 49, find the correct moments.
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- Given the mean and SD of the eight forms of employment in PEAR INC., calculate the z-scores for the individuals who took the exams in the different countries. ROUND Z-SCORES TO THREE DECIMAL PLACES; WRITE Z-SCORES WITH A SIGN (ex. -1.204 for negative z-score and +1.204 for positive) Description Quiz 11: Z-Scores ROUND Z-SCORES TO THREE DECIMAL PLACES (to the nearest thousandth). EACH Z-SCORE SHOULD HAVE A + OR - SIGN IN FRONT TO INDICATE POSITIVE OR NEGATIVE VALUE. Use the data below: Eight forms of an employment exam (one in each country of expansion) are given by PEAR INC. The overall (population) mean and standard deviations of these eight forms are found in the table below. TEST LOCATION MEAN ( ) Standard Deviation ( ) Argentina 82 7 Belgium 39 3.5 China 125 11.5 Denmark 60 5.2 Egypt 92 8.5 France 420 36 Greece 160 14.5 Holland 75 6.5 1. Egypt mean = 92; SD = 8.5 Emir took the test in Egypt and scored 90; Emir's Z-score is:…A company that supplies LP gas for heating keeps data on the low temperature for each day of each month. It sum-marizes these data by finding the mean, median, standard deviation and interquartile range. The company assumesthat people use the LP gas for heat when the temperature is below 70°, so it creates a second set of data by subtract-ing 70 from each daily low temperature. Which of the four summary statistics will change for this second data set?A) mean and median onlyB) mean and standard deviation onlyC) median and IQR onlyD) standard deviation and IQR onlyE) mean, median, standard deviation, and IQRNabisco claims that Chip Ahoy Cookies have an x ̅=28.67 chocolate chips per cookie with a SD=2.67. You randomly select 36 cookies from a new bag and carefully remove all the chocolate chips from each of the 36 cookies. You find the mean of the chocolate chips for the 36 cookies is 24.27 chocolate chips per cookie. Calculate the standard error for the chocolate chips in your experiment. (round to the nearest hundredth).
- 15 Mean of 100 items was 50. Later on it was found that two items were misread as 92 and 8 instead of 192 and 88. Find the correct mean. Given N=100 , X=50Hellen has just started a new years competition for her local climbing gym. There are two categories for this competition: singles and group (18 people). The rules are simple, put in the most hours in one months time and you get a guided tour to climb Ten Sleep canyon. She knows from running this competition over the years that the number of hours climbers at her gym spend training during this competiton is approximately normal and their mean competition hours per month in the gym are 24 hrs with a standard devaition of 6 hrs If someone puts in between 25.5-32.1 hours on the wall they get a Mountain Goat shirt. What percent of the singles competitors is expected to get a shirt? In the group stage this year the winning group was in the 81 th percentile. What was their average time? The group stage is up for getting Gecko Socks if they also land between 25.5-32.1 hours on the wall on average. What prercent of the groups are expected to qualify for the socks?The mean and S.D. of 20 items were found to be 12 and 6 respectively. On checking it was discovered that items which should correctly read as 11 and 21 had been wrongly taken as 15 and 27 respectively. Find the correct values of mean and S.D.
- Q7: Compute 75th percentile for the data given 45, 32, 37, 46, 39, 36, 41, 48, 36.The mean for the following values 10 ,60 ,50 , 30 , 40 , 20 is 34 Select one: True • FalseThe mean marks of 100 students were found to be 40. Later on it was discovered that a score of 53 was misread as 83. Find the correct mean corresponding to the correct score.