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For a beam of a light with a wavelength of 529 nm calculate the energy in kJ for 6 × 1023 of photons. Planck's constant, h = 6.626 × 10-34 J.s; the speed of light in a vacuum, c = 3.00 × 108 m/s; 1 nm = 10° m; NA = 6.022 × 1023 Answer: Energy (k) =

For a beam of a light with a wavelength of 529 nm calculate the energy in kJ for 6 × 1023 of photons. Planck's constant, h = 6.626 × 10-34 J.s; the speed of light in a vacuum, c = 3.00 × 108 m/s; 1 nm = 10° m; NA = 6.022 × 1023 Answer: Energy (k) =

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Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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### Problem Statement Calculate the energy in kilojoules (kJ) for \(6 \times 10^{23}\) photons of light with a wavelength of 529 nm. ### Given Data - **Planck's constant,** \( h = 6.626 \times 10^{-34} \, \text{J}\cdot\text{s} \) - **The speed of light in a vacuum,** \( c = 3.00 \times 10^{8} \, \text{m/s} \) - **Conversion factor for nanometers to meters,** \( 1 \, \text{nm} = 10^{-9} \, \text{m} \) - **Avogadro's number,** \( N_A = 6.022 \times 10^{23} \) ### Solution #### Answer: \[ \text{Energy (kJ)} = \] --- This problem involves calculating the energy associated with a given number of photons using the known constants of Planck’s constant, the speed of light, and Avogadro's number. The conversion between nanometers and meters is necessary to match units for calculating energy using the equation: \[ E = \frac{h \cdot c}{\lambda} \] where \( E \) is energy, \( h \) is Planck’s constant, \( c \) is the speed of light, and \( \lambda \) is the wavelength.
Transcribed Image Text:### Problem Statement Calculate the energy in kilojoules (kJ) for \(6 \times 10^{23}\) photons of light with a wavelength of 529 nm. ### Given Data - **Planck's constant,** \( h = 6.626 \times 10^{-34} \, \text{J}\cdot\text{s} \) - **The speed of light in a vacuum,** \( c = 3.00 \times 10^{8} \, \text{m/s} \) - **Conversion factor for nanometers to meters,** \( 1 \, \text{nm} = 10^{-9} \, \text{m} \) - **Avogadro's number,** \( N_A = 6.022 \times 10^{23} \) ### Solution #### Answer: \[ \text{Energy (kJ)} = \] --- This problem involves calculating the energy associated with a given number of photons using the known constants of Planck’s constant, the speed of light, and Avogadro's number. The conversion between nanometers and meters is necessary to match units for calculating energy using the equation: \[ E = \frac{h \cdot c}{\lambda} \] where \( E \) is energy, \( h \) is Planck’s constant, \( c \) is the speed of light, and \( \lambda \) is the wavelength.
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