For a 20 kVA, 250 V, 6 pole, 3-phase, Y-connected alternator has an AC armature resistance between terminals of 0.16-ohm, leakage reactance of 0.3 ohms per phase. Field resistance 75°C is 14.3 ohms, If 3A; friction and windage loss = 350 Watts; core loss =180 Watts. = Calculate: a) %n at 80% of the load, 0.8 pf lagging b) maximum efficiency at 0.8 pf lagging

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Kindly answer the what is asked wherein the %n at full load, 0.8 lagging is 90.48%, Solve for the %n at 80% of the load and the nmax of it with 0.8pf lagging. Moreover, show me a complete, clean, step by step solution so that I can understand. 

 

For a 20 kVA, 250 V, 6 pole, 3-phase, Y-connected alternator
has an AC armature resistance between terminals of 0.16-ohm,
leakage reactance of 0.3 ohms per phase. Field resistance
75°C is 14.3 ohms, If 3A; friction and windage loss = 350
Watts; core loss =180 Watts.
=
Calculate:
a) %n at 80% of the load, 0.8 pf lagging
b) maximum efficiency at 0.8 pf lagging
Transcribed Image Text:For a 20 kVA, 250 V, 6 pole, 3-phase, Y-connected alternator has an AC armature resistance between terminals of 0.16-ohm, leakage reactance of 0.3 ohms per phase. Field resistance 75°C is 14.3 ohms, If 3A; friction and windage loss = 350 Watts; core loss =180 Watts. = Calculate: a) %n at 80% of the load, 0.8 pf lagging b) maximum efficiency at 0.8 pf lagging
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