for 5.00 seconds. After this 5.00-second interval, the object then travels as a projectile. Determine the maximum height of the projectile.

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An object is propelled from the origin with acceleration
à = (4.00î + 2.00§)mls²
and initial velocity
Vo = (8.00î + 12.0)mls
for 5.00 seconds. After this 5.00-second interval, the object then travels as a
projectile. Determine the maximum height of the projectile.
Transcribed Image Text:An object is propelled from the origin with acceleration à = (4.00î + 2.00§)mls² and initial velocity Vo = (8.00î + 12.0)mls for 5.00 seconds. After this 5.00-second interval, the object then travels as a projectile. Determine the maximum height of the projectile.
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Step 1

Projectile

A projectile is an object that is thrown without any fuel. Generally, a projectile is thrown with a velocity that makes an angle with respect to the horizontal. Examples of a projectile are meteors and an artillery gun firing at enemy positions. 

The trajectory of a projectile thrown with an initial velocity v at an angle θ with respect to the horizontal is

Advanced Physics homework question answer, step 1, image 1

H is the maximum height attained by the projectile and R is the range of the projectile. 

The x and y components of the initial velocity of the projectile are

vx=vcosθvy=vsinθ

Therefore the vertical displacement of the projectile with the y component velocity at that moment is given by

vy'2=vy2-2gy

Here g is the acceleration due to gravity. Now at the highest point of the trajectory, the y component of the velocity is zero. If H is the maximum height attained by the projectile, we get

0=vy2-2gH2gH=vy2H=vy22g=v2sin2θ2g

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