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For 1.25 mol of an ideal gas, Pexternal = P = 350 x 103 pa. The temperature is changed from 135°C to 21.2°C, and Cym = 3R/2. Calculate q, w, AU, and AH. %3D

For 1.25 mol of an ideal gas, Pexternal = P = 350 x 103 pa. The temperature is changed from 135°C to 21.2°C, and Cym = 3R/2. Calculate q, w, AU, and AH. %3D

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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2. For 1.25 mol of an ideal gas, P temperature is changed from 135°C to 21.2°C, and Cy.m = 3R/2. Calculate q, w, AU, and AH. = P = 350 x 10³ pa. The %3D external
Transcribed Image Text:2. For 1.25 mol of an ideal gas, P temperature is changed from 135°C to 21.2°C, and Cy.m = 3R/2. Calculate q, w, AU, and AH. = P = 350 x 10³ pa. The %3D external
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