Fonsi Consider a mixture of air and gasoline vapor in a cylinder with a piston. The original volume is 40. cm³. If the combustion of this mixture releases 950. J of energy, to what volume will the gases expand against a constant pressure of 650. torr if all the energy of combustion is converted into work to push back the piston?

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Number 37 please. I am getting 1111 liters. Answe is 11 liters. The question begins "consider a mixture of air and gasoline vapor"

**Transcribed Text for Educational Website**

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**Problem 37:**

Consider a mixture of air and gasoline vapor in a cylinder with a piston. The original volume is 40. cm³. If the combustion of this mixture releases 950. J of energy, to what volume will the gases expand against a constant pressure of 650. torr if all the energy of combustion is converted into work to push back the piston?

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**Problem 38:**

As a system increases in volume, it absorbs 52.5 J of energy in the form of heat from the surroundings. The piston is working against a pressure of 0.500 atm. The final volume of the system is 58.0 L. What was the initial volume of the system if the internal energy of the system decreased by 102.5 J?

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**Problem 39:**

A balloon filled with 39.1 moles of helium has a volume of 876 L at 0.0°C and 1.00 atm pressure. The temperature of the balloon is increased to 38.0°C as it expands to a volume of [incomplete data]. 

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*Source: Cengage Learning 2014.*
Transcribed Image Text:**Transcribed Text for Educational Website** --- **Problem 37:** Consider a mixture of air and gasoline vapor in a cylinder with a piston. The original volume is 40. cm³. If the combustion of this mixture releases 950. J of energy, to what volume will the gases expand against a constant pressure of 650. torr if all the energy of combustion is converted into work to push back the piston? --- **Problem 38:** As a system increases in volume, it absorbs 52.5 J of energy in the form of heat from the surroundings. The piston is working against a pressure of 0.500 atm. The final volume of the system is 58.0 L. What was the initial volume of the system if the internal energy of the system decreased by 102.5 J? --- **Problem 39:** A balloon filled with 39.1 moles of helium has a volume of 876 L at 0.0°C and 1.00 atm pressure. The temperature of the balloon is increased to 38.0°C as it expands to a volume of [incomplete data]. --- *Source: Cengage Learning 2014.*
This image contains handwritten equations and notes related to a physics or engineering problem involving work and volume changes.

On the left, there is a rough sketch of a cylinder with a label "1.855" and an arrow pointing downward. It may represent a piston or a similar mechanism. The sides of the cylinder have the label "400 l" (possibly 400 L) and the number "1000" below it, which might relate to volume or height measurements.

Equations and calculations are shown on the right side:

1. **\( 950 \, \text{J} \)** - This represents an energy quantity, likely work done or energy transferred, measured in Joules.
   
2. **\( W = -P \Delta V \)** - This is the formula for work done by or on a system due to volume change, where \( P \) is pressure and \( \Delta V \) is the change in volume.

3. **\( 950 = (0.855)(V_2 - 0.066) \)** - This equation relates the energy to a change in volume and a coefficient of 0.855. There seems to be a scribbled correction around the number 0.066, indicating an error or reconsideration of a value.

4. The subsequent equations continue the process of solving for \( V_2 \), the final volume:

   \[
   950 - \frac{650}{760} = 0.855
   \]

5. **\( 950 = (0.855)V_2 + 934.0207 \)** - This appears to be a manipulation of the previous equation to isolate \( V_2 \).

There is no clear plot or diagram other than the cylinder sketch. The calculations appear to be leading to the derivation of \( V_2 \), which is an unknown parameter in the context of the problem involving work and volume change.
Transcribed Image Text:This image contains handwritten equations and notes related to a physics or engineering problem involving work and volume changes. On the left, there is a rough sketch of a cylinder with a label "1.855" and an arrow pointing downward. It may represent a piston or a similar mechanism. The sides of the cylinder have the label "400 l" (possibly 400 L) and the number "1000" below it, which might relate to volume or height measurements. Equations and calculations are shown on the right side: 1. **\( 950 \, \text{J} \)** - This represents an energy quantity, likely work done or energy transferred, measured in Joules. 2. **\( W = -P \Delta V \)** - This is the formula for work done by or on a system due to volume change, where \( P \) is pressure and \( \Delta V \) is the change in volume. 3. **\( 950 = (0.855)(V_2 - 0.066) \)** - This equation relates the energy to a change in volume and a coefficient of 0.855. There seems to be a scribbled correction around the number 0.066, indicating an error or reconsideration of a value. 4. The subsequent equations continue the process of solving for \( V_2 \), the final volume: \[ 950 - \frac{650}{760} = 0.855 \] 5. **\( 950 = (0.855)V_2 + 934.0207 \)** - This appears to be a manipulation of the previous equation to isolate \( V_2 \). There is no clear plot or diagram other than the cylinder sketch. The calculations appear to be leading to the derivation of \( V_2 \), which is an unknown parameter in the context of the problem involving work and volume change.
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