following Normal distribution with u = 100 and standard deviation o = 15. What is theProbability that a randomly chosen person has IQ between 80 and 120.6. Let X have a normal distribution with u = 12 and o 3. Find the probability that an xvalue selected at random from this distribution is between 11 and 14?funtional life that is nomally distributed with mean of 2.2Di

Given DataMean = 12Standard deviation = 3probability that X-value selected at randomly from this…

Answered: following Normal distribution with u =…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Suppose Abby tracks her travel time to work for 60 days and determines that her mean travel time, in minutes, is 35.6. Assume x). decimal places. P(X > x) = 0.2946 In order to find x, first find the value z such that 29.46% of the total area under 36.32 min the standard normal density curve is to the right of z. You can find z using this Incorrect standard normal distribution table or this list of software manuals. The z-score formula, where u is the mean and o is the standard deviation, can be used to convert z into travel times. %3D Be sure to round your answer correctly to two decimal places.
On average, indoor cats live to 13 years old with a standard deviation of 2.2 years. Suppose that the distribution is normal. Let X = the age at death of a randomly selected indoor cat. Round answers to 4 decimal places where possible. ROUND TO 4 DECIMAL PLACES PLEASE! THANK YOU b. Find the probability that an indoor cat dies when it is between 10.8 and 13.2 years old. c. The middle 40% of indoor cats' age of death lies between what two numbers? Low: years High: years
A population of values has a normal distribution with �=105.6 and �=10.5. Find the probability that a single randomly selected value is greater than 102.1. Round your answer to four decimal places. �(�>102.1)= Find the probability that a randomly selected sample of size �=66 has a mean greater than 102.1. Round your answer to four decimal places. �(�>102.1)=
The population of scores on a nationally standardized test forms a normal distribution with a mean of 300 and a standard deviation of 50. If you take a random sample of n = 25 students, what is the probability that the sample mean will be less than M = 280? Pls explain! Thx!
The mean daily production of a herd of cows is assumed to be normally distributed with a mean of 36 liters, and standard deviations of 16 liters. I What is the probability that daily production is less than 43 liters (round your answer to 4 decimals) CS Scanned with CamScanner
A normal distribution has a mean of u = 50 and 0 = 12 if one score is randomly selected for distribution what is the probability of randomly selectingt a score that is X < 56
Scores on a standardized exam are known to follow a normal distribution with standard deviation σσ = 17. A researcher randomly selects 85 students and computes their average score. He reports that the mean score is 76.3, with a margin of error of 2.792. How confident are you that the mean score for all students taking the exam is in the interval (73.508, 79.092)? Confidence =
A population of values has a normal distribution with �=233.1 and �=78.3. Find the probability that a single randomly selected value is between 207.1 and 270.9. Round your answer to four decimal places.�(207.1<�<270.9)= Find the probability that a randomly selected sample of size �=44 has a mean between 207.1 and 270.9. Round your answer to four decimal places.
The average THC content of marijuana sold on the street is 9.7%. Suppose the THC content is normally distributed with standard deviation of 1%. Let X be the THC content for a randomly selected bag of marijuana that is sold on the street. Round all answers to 4 decimal places where possible,a. What is the distribution of X? X ~ N(Correct,Correct) b. Find the probability that a randomly selected bag of marijuana sold on the street will have a THC content greater than 8.4. c. Find the 65th percentile for this distribution. % Submit QuestionQuestion 7
1/ The patient recovery time from a particular surgical procedure is normally distributed with a mean of 4 days and a standard deviation of 2 days. Let X be the recovery time for a randomly selected patient. Round all answers to 4 decimal places where possible.a. What is the distribution of X? X ~ N(,)b. What is the median recovery time? daysc. What is the Z-score for a patient that took 5.1 days to recover? d. What is the probability of spending more than 4.8 days in recovery? e. What is the probability of spending between 3.5 and 4.1 days in recovery? f. The 90th percentile for recovery times is days. 2/The amount of time that people spend at Grover Hot Springs is normally distributed with a mean of 79 minutes and a standard deviation of 15 minutes. Suppose one person at the hot springs is randomly chosen. Let X = the amount of time that person spent at Grover Hot Springs . Round all answers to 4 decimal places where possible.a. What is the distribution of X? X ~ N(,)b. Find the…
Not everyone pays the same price with the same model as a car to figure illustrate a normal distribution for the price pay for a particular model of a new car the main is 18,000 and the standard deviationis 1000 used to 68 -95 -99.7 rule to find what percentage of buyers pay between 16,000 and 20,000
The average number of miles (in thousands) that a car's tire will function before needing replacement is 72 and the standard deviation is 18. Suppose that 50 randomly selected tires are tested. Round all answers to 4 decimal places where possible and assume a normal distribution. 1. If a randomly selected individual tire is tested, find the probability that the number of miles (in thousands) before it will need replacement is between 73.9 and 76.9. 2. For the 50 tires tested, find the probability that the average miles (in thousands) before need of replacement is between 73.9 and 76.9.

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