Following is the variation of the field standard penetration number (N0) in a sand deposit: Depth (m) 1.5 3 8 4.5 9. 6 8 7.9 13 14 The groundwater table is located at a depth of 6 m. Given: the dry unit weight of sand from 0 to a depth of 6 m is 18 kN/m², and the saturated unit weight of sand for depth 6 to 12 m is 20.2 kN/m³. Use the relationship given in Eq. (3.13) to calculate the corrected penetration numbers. 10.5 1 CN Pa
Following is the variation of the field standard penetration number (N0) in a sand deposit: Depth (m) 1.5 3 8 4.5 9. 6 8 7.9 13 14 The groundwater table is located at a depth of 6 m. Given: the dry unit weight of sand from 0 to a depth of 6 m is 18 kN/m², and the saturated unit weight of sand for depth 6 to 12 m is 20.2 kN/m³. Use the relationship given in Eq. (3.13) to calculate the corrected penetration numbers. 10.5 1 CN Pa
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Related questions
Question
Refer to Problem 3.4. Using Eq. (3.28), determine the average relative density of the sand. Assume it is a fine sand. Use Eq. (3.13) to obtain (N1)60.
![Following is the variation of the field standard penetration number (N0) in a sand
deposit:
Depth (m)
1.5
3
8
4.5
9.
6
8
7.9
13
14
The groundwater table is located at a depth of 6 m. Given: the dry unit weight of
sand from 0 to a depth of 6 m is 18 kN/m², and the saturated unit weight of sand for
depth 6 to 12 m is 20.2 kN/m³. Use the relationship given in Eq. (3.13) to calculate the
corrected penetration numbers.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F71c927ea-e574-4cab-83ed-fe543f0ac29d%2F122ef0b1-d267-4bf5-8244-a3dd453b387b%2Fq02v7e_processed.png&w=3840&q=75)
Transcribed Image Text:Following is the variation of the field standard penetration number (N0) in a sand
deposit:
Depth (m)
1.5
3
8
4.5
9.
6
8
7.9
13
14
The groundwater table is located at a depth of 6 m. Given: the dry unit weight of
sand from 0 to a depth of 6 m is 18 kN/m², and the saturated unit weight of sand for
depth 6 to 12 m is 20.2 kN/m³. Use the relationship given in Eq. (3.13) to calculate the
corrected penetration numbers.
![10.5
1
CN
Pa](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F71c927ea-e574-4cab-83ed-fe543f0ac29d%2F122ef0b1-d267-4bf5-8244-a3dd453b387b%2F5h4xmog_processed.png&w=3840&q=75)
Transcribed Image Text:10.5
1
CN
Pa
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