8. What is AX value after the following statement is executed? MOV EAX, 13456H AX = ? Register array Program EAX 3 3 3 3 62 91 MOV EAX,13456H EBX -13456H- Since the previous AX register is 0x6291H, by moving the 0x13456H into the previous EAX, it will be overwritten the entire register, most importantly, the previous AX value will be replaced into a new value of AX. Therefore AX = 0x3456H, since AX = AH + AL, therefore (AH = 45) & (AL = 56H). Following figure was plotted for an unsigned integer using little-endian format, please give a representation of the data (a doubleword). 0000: 78 0001: 56 0002: 34 0003: 12 In the unsigned integer 78h would be stored in the first byte, 56h would be stored in the second byte, then the remaining bytes which is the offset of 0002 and 0003 Therefore, the unsigned integer using little endian format in doubleword is 12345678h

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
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8. What is AX value after the following statement is executed?
MOV EAX, 13456H
AX = ?
Register array
Program
EAX
3 3 3 3
62
91
MOV EAX,13456H
EBX
-13456H-
Since the previous AX register is 0x6291H, by moving the 0x13456H into the previous
EAX, it will be overwritten the entire register, most importantly, the previous AX value
will be replaced into a new value of AX. Therefore AX = 0x3456H, since AX = AH + AL,
therefore (AH = 45) & (AL = 56H).
Transcribed Image Text:8. What is AX value after the following statement is executed? MOV EAX, 13456H AX = ? Register array Program EAX 3 3 3 3 62 91 MOV EAX,13456H EBX -13456H- Since the previous AX register is 0x6291H, by moving the 0x13456H into the previous EAX, it will be overwritten the entire register, most importantly, the previous AX value will be replaced into a new value of AX. Therefore AX = 0x3456H, since AX = AH + AL, therefore (AH = 45) & (AL = 56H).
Following figure was plotted for an unsigned integer using
little-endian format, please give a representation of the data (a
doubleword).
0000:
78
0001:
56
0002:
34
0003:
12
In the unsigned integer 78h would be stored in the first byte, 56h would be stored in the
second byte, then the remaining bytes which is the offset of 0002 and 0003
Therefore, the unsigned integer using little endian format in doubleword is 12345678h
Transcribed Image Text:Following figure was plotted for an unsigned integer using little-endian format, please give a representation of the data (a doubleword). 0000: 78 0001: 56 0002: 34 0003: 12 In the unsigned integer 78h would be stored in the first byte, 56h would be stored in the second byte, then the remaining bytes which is the offset of 0002 and 0003 Therefore, the unsigned integer using little endian format in doubleword is 12345678h
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