-following expression as a complex number in polar form = evi = + + 8-j6 J² magnitude 1 phase = 14° ²= -1 1/14° + 3/5 + 8-16 √√8² +6² 10 magnitude= phase= tan E tan" (=) = -36.86 1/14 + 3/3 + 10/-36.86 18.72 -16.38 polar form 5/30 = 2 L-15 2.5 L45 + 2L5 # 2-21 - 2e³5 2-ja २ - j२ magnitude = 2 phase s magnitude = phase = √√√2² +2²= 2√3 tan² (-2-) =-45" 2.5/45 + 2/5 √2-45 2.5/45 + 0.707/50 3.204/46.101 pour form 5/30 15 و = 2L-15 2.5 L 45* 2-2j 3 C + Res 2-ja + 2L5 २ - j२ magnitude = 2 phase s' magnitude = phase = √√2² +2² = 2√² tam ¹ (2) = -45² 2.5/45 + 2/5 √22L-45 2.5 45 + 0.707 L50' 3.204/46. 101 pour fam
-following expression as a complex number in polar form = evi = + + 8-j6 J² magnitude 1 phase = 14° ²= -1 1/14° + 3/5 + 8-16 √√8² +6² 10 magnitude= phase= tan E tan" (=) = -36.86 1/14 + 3/3 + 10/-36.86 18.72 -16.38 polar form 5/30 = 2 L-15 2.5 L45 + 2L5 # 2-21 - 2e³5 2-ja २ - j२ magnitude = 2 phase s magnitude = phase = √√√2² +2²= 2√3 tan² (-2-) =-45" 2.5/45 + 2/5 √2-45 2.5/45 + 0.707/50 3.204/46.101 pour form 5/30 15 و = 2L-15 2.5 L 45* 2-2j 3 C + Res 2-ja + 2L5 २ - j२ magnitude = 2 phase s' magnitude = phase = √√2² +2² = 2√² tam ¹ (2) = -45² 2.5/45 + 2/5 √22L-45 2.5 45 + 0.707 L50' 3.204/46. 101 pour fam
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
TRANSCRIBE IN DIGITAL FORMAT THE SOLUTION
Transcribed Image Text:following expression
a
| J
}}
evlao
expression as a complex number in polar form
ㅠ
evili
| |
+ 9/3² + 8-16
J²
T
magnitude 1
phase = 14°
2
y² = −1
1/14° + 9/3+ 8-jo
-1
... 8-j6
2
8² +6²
10
magnitude =
phase= tan²1/-6
tań
tan" (-683)
-
36.86
1/ 14⁰ + 9/3² + 10 L-36-86°
18.72 / -16.38 polar form
pets
→
5/30°
11
2 L-15°
2.5L45°
2-21
ㅠ
V
+
pers
2-ja
+ 2/5°
+
2.5/45 +
२-j2
magnitude = &
phase = 5°
magnitude
phase
=
11
2² +2²
tamil
form" (-2-) =-45²
2/5°
√2x2 /- 45°
2.5/45 + 0.707 L50°
3.204 L46.101
2√3
polar tom
C
€
€
€
10000
с
E
Pets
→
5/30°
=
2 L-15°
2-21
2.5 L45 + 225
२ - j२
ㅠ
V
+
0
pers
2-ja
magnitude = &
phase
= 5°
=
magnitude
phase
=
11
√√2² +2² = 2√2
tant
*¹(-²)
2
2.5 L45° + 2/5°
√2x2 L-45
2.5/45 + 0.707 L50
3.204 L46.101°
= -45°
polar tom
€
€
0 0 0 0 0 0 0 0
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