Follow the curved arrows and draw the products of the following reaction. Include all lone pairs and charges as appropriate. Ignore inorganic byproducts. Br H3C CH3 H. НО

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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**Instructions:**

Follow the curved arrows and draw the products of the following reaction. Include all lone pairs and charges as appropriate. Ignore inorganic byproducts.

**Reaction Diagram Explanation:**

- The diagram shows a chemical structure with a bromine (Br) atom attached to a carbon chain.
- There are several curved arrows indicating electron movement:
  - The first arrow is from the lone pair of electrons on the hydroxide ion (HO⁻) towards the hydrogen atom (H) attached to the carbon atom adjacent to the Br.
  - The second arrow shows the electrons from the C-H bond being donated to form a double bond between the two adjacent carbons.
  - The third arrow indicates the electrons from the C-Br bond moving towards the Br, indicating that it will leave as a bromide ion (Br⁻).

**Note:** The arrows signify the mechanism of the reaction and help determine the structure of the resulting product. The reaction is likely a type of nucleophilic substitution or elimination.
Transcribed Image Text:**Instructions:** Follow the curved arrows and draw the products of the following reaction. Include all lone pairs and charges as appropriate. Ignore inorganic byproducts. **Reaction Diagram Explanation:** - The diagram shows a chemical structure with a bromine (Br) atom attached to a carbon chain. - There are several curved arrows indicating electron movement: - The first arrow is from the lone pair of electrons on the hydroxide ion (HO⁻) towards the hydrogen atom (H) attached to the carbon atom adjacent to the Br. - The second arrow shows the electrons from the C-H bond being donated to form a double bond between the two adjacent carbons. - The third arrow indicates the electrons from the C-Br bond moving towards the Br, indicating that it will leave as a bromide ion (Br⁻). **Note:** The arrows signify the mechanism of the reaction and help determine the structure of the resulting product. The reaction is likely a type of nucleophilic substitution or elimination.
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