College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![### Force Diagram Analysis
The image contains a diagram of a block with four forces acting on it. These forces are represented by arrows:
- **F_grav**: The gravitational force acting downward, labeled as \( F_{grav} = 68 \, \text{N} \).
- **F_norm**: The normal force acting upward, opposing gravity.
- **F_app**: The applied force acting to the right, labeled as \( F_{app} = 23.5 \, \text{N} \).
- **F_frict**: The frictional force acting to the left, opposing the applied force.
### Problem Statement
The task is to find the coefficient of friction (\(\mu\)) of the block using the provided diagram and given data.
### Given Data
- Gravitational force, \( F_{grav} = 68 \, \text{N} \)
- Applied force, \( F_{app} = 23.5 \, \text{N} \)
- Acceleration, \( a = 0.5 \, \text{m/s}^2 \)
To find the coefficient of friction, we'll use the following equation:
\[ \mu = \frac{F_{frict}}{F_{norm}} \]
Given that \( F_{norm} = F_{grav} \) when the block is on a flat surface with no vertical acceleration, \( F_{norm} = 68 \, \text{N} \).
The net force \( F_{net} \) in the horizontal direction can be calculated using Newton’s second law:
\[ F_{net} = m \cdot a \]
Where \( m \) is the mass of the block, and \( a = 0.5 \, \text{m/s}^2 \).
Using the equation \( F_{net} = F_{app} - F_{frict} \), we can solve for \( F_{frict} \). Then, substitute \( F_{frict} \) and \( F_{norm} \) into the equation for \(\mu\) to find the coefficient of friction.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F04527971-3b41-4b11-a76b-e9283385d7b6%2F70596fc6-731a-4bc2-8637-18ebfcd28fd3%2Fwxwi7kq_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Force Diagram Analysis
The image contains a diagram of a block with four forces acting on it. These forces are represented by arrows:
- **F_grav**: The gravitational force acting downward, labeled as \( F_{grav} = 68 \, \text{N} \).
- **F_norm**: The normal force acting upward, opposing gravity.
- **F_app**: The applied force acting to the right, labeled as \( F_{app} = 23.5 \, \text{N} \).
- **F_frict**: The frictional force acting to the left, opposing the applied force.
### Problem Statement
The task is to find the coefficient of friction (\(\mu\)) of the block using the provided diagram and given data.
### Given Data
- Gravitational force, \( F_{grav} = 68 \, \text{N} \)
- Applied force, \( F_{app} = 23.5 \, \text{N} \)
- Acceleration, \( a = 0.5 \, \text{m/s}^2 \)
To find the coefficient of friction, we'll use the following equation:
\[ \mu = \frac{F_{frict}}{F_{norm}} \]
Given that \( F_{norm} = F_{grav} \) when the block is on a flat surface with no vertical acceleration, \( F_{norm} = 68 \, \text{N} \).
The net force \( F_{net} \) in the horizontal direction can be calculated using Newton’s second law:
\[ F_{net} = m \cdot a \]
Where \( m \) is the mass of the block, and \( a = 0.5 \, \text{m/s}^2 \).
Using the equation \( F_{net} = F_{app} - F_{frict} \), we can solve for \( F_{frict} \). Then, substitute \( F_{frict} \) and \( F_{norm} \) into the equation for \(\mu\) to find the coefficient of friction.
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