Fnb Lab report 1 Q 20 = 155 #ra X A Ch 8 Chemical.. X 2. For the reaction Ch3 [0.5] [0.15]³ [1]" 2NH3 (g) 20 (2 Kc N₂(g) + 3H₂ (g) Equilibrium constant is 3×10-³ at temperature T. A 1.0 L mixture containing 1.0 mole of NH3, 0.50 mole of N₂, and 0.15 mole of H₂ is prepared at this temperature. When equilibrium is reached, = X NO shift will occur X there will be more NH3 gas X 249 4 Kinetics.. X A. B. C. there will be less N₂ gas but more H₂ gas D. there will be less NH3 and N2 gases X there will be more N₂ and H₂ gases. E. 1.6875x10-3

Fnb Lab report 1 Q 20 = 155 #ra X A Ch 8 Chemical.. X 2. For the reaction Ch3 [0.5] [0.15]³ [1]" 2NH3 (g) 20 (2 Kc N₂(g) + 3H₂ (g) Equilibrium constant is 3×10-³ at temperature T. A 1.0 L mixture containing 1.0 mole of NH3, 0.50 mole of N₂, and 0.15 mole of H₂ is prepared at this temperature. When equilibrium is reached, = X NO shift will occur X there will be more NH3 gas X 249 4 Kinetics.. X A. B. C. there will be less N₂ gas but more H₂ gas D. there will be less NH3 and N2 gases X there will be more N₂ and H₂ gases. E. 1.6875x10-3

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

Is it correct

4:17 PM Mon 13 Nov
X
Q
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Fnb Lab report 1
no
Q =
第1頁,共5頁
X
Ch 8 Chemical.. X
2. For the reaction
Ch3
20 / ²
2NH3 (g)
[0.5] [015]³
[1]"
23-24 IGC A2 ✓
Кс
249 4 Kinetics..
NO shift will occur
there will be more NH3 gas X
N₂ (g) + 3H2 (g)
T
A.
B.
C. there will be less N₂ gas but more H₂ gas
D. there will be less NH3 and N2 gases X
there will be more N₂ and H₂ gases.
E.
Equilibrium constant is 3×10-³ at temperature T. A 1.0 L mixture containing 1.0 mole
of NH3, 0.50 mole of N₂, and 0.15 mole of H₂ is prepared at this temperature. When
equilibrium is reached,
1.6875x10-3
<Kc
x
иг
249 4 Kinetics... X
2N113(g) =
+
-2x
Ch 8 Chemical..
= N₂ly) + ³H₂ly)
0.9 0.19
+ 3x
shift to right
+ X
38%
23-24 IGC A2

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