FMA o Mebini, Devuo de Oro Quarter/Month: Score: Combination The number of combinations of z objects taken rat a time is C(r)- XMPLE 1 How many ways can you seleet a commitree of 4 students out of 10 students? UTION The arrangement or order of the students chosen is not important. Therefore, this is a combination problem, where n=10 and r=4. C(n,r)= C(10,4)= 10! 4!(10-4)! 10! 4!(6!) 10-9-8-7-61 413 2-1-6! = 210 EXAMPLE 2. How many triangles can be drawn on a plane using 4 non- collinear points? solurION A triangle is a figure formed by three segments joining three (3) non collinear points (r= 3). Ifthere are 4 points (=4) on the plane, then 4! 4.3)= 3:(4-3)! 311! 4.3! 3!

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can you please solve this, I have a example combinations on that so please solve then answer??
ot Mebini,
Deveo de Oro
FMA
Quarter/Month:
Score:
Combination
The number of combinations of z objects taken rat a
time is
C(r)-
r(n-r)"
EXAMPLE 1
How many ways can you seleet a commitree of 4 studentsS
out of 10 students?
SOLUTTON
The arrangement or order of the students chosen is not important.
Therefore, this is a combination problem, where n=10 and r=4.
r!(n-r)!
C(10,4)=
10!
4!(10-4)!
10!
4!(6!)
10-9.8-7-61
4.3 2-1-6!
= 210
EXAMPLE 2.
How many triangles can be drawn on a plane using 4 non-
collinear points?
SOLUTION
A triangle is a figure formed by three segments joining three (3) non
collinear points (r3).
If there are 4 points (=4) on the plane, then
4!
4.3)%=
3:(4-3)!
4!
311!
4.3!
31
Transcribed Image Text:ot Mebini, Deveo de Oro FMA Quarter/Month: Score: Combination The number of combinations of z objects taken rat a time is C(r)- r(n-r)" EXAMPLE 1 How many ways can you seleet a commitree of 4 studentsS out of 10 students? SOLUTTON The arrangement or order of the students chosen is not important. Therefore, this is a combination problem, where n=10 and r=4. r!(n-r)! C(10,4)= 10! 4!(10-4)! 10! 4!(6!) 10-9.8-7-61 4.3 2-1-6! = 210 EXAMPLE 2. How many triangles can be drawn on a plane using 4 non- collinear points? SOLUTION A triangle is a figure formed by three segments joining three (3) non collinear points (r3). If there are 4 points (=4) on the plane, then 4! 4.3)%= 3:(4-3)! 4! 311! 4.3! 31
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