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Flow of Water from a Tank Water flows from a tank of constant cross-sectional area 40 ft² through an orifice of constant cross-sectional area ft² located at the bottom of the tank. Initially, the height 름 of the water in the tank was 20 ft, and t s later it was given by the equation ( 2√/h + t-2√/20 = 0 0sts 40√/20. How fast (in ft/s) was the height of the water decreasing when its height was 16 ft?

Flow of Water from a Tank Water flows from a tank of constant cross-sectional area 40 ft² through an orifice of constant cross-sectional area ft² located at the bottom of the tank. Initially, the height 름 of the water in the tank was 20 ft, and t s later it was given by the equation ( 2√/h + t-2√/20 = 0 0sts 40√/20. How fast (in ft/s) was the height of the water decreasing when its height was 16 ft?

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Flow of Water from a Tank Water flows from a tank of constant cross-sectional area 40 ft2 through an orifice of constant cross-sectional area ft² located at the bottom of the tank. Initially, the height of the water in the tank was 20 ft, and t s later it was given by the equation Ⓡ 2√/h+t-2√/20 = 0 0st≤ 40√20. How fast (in ft/s) was the height of the water decreasing when its height was 16 ft? ft/s
Transcribed Image Text:Flow of Water from a Tank Water flows from a tank of constant cross-sectional area 40 ft2 through an orifice of constant cross-sectional area ft² located at the bottom of the tank. Initially, the height of the water in the tank was 20 ft, and t s later it was given by the equation Ⓡ 2√/h+t-2√/20 = 0 0st≤ 40√20. How fast (in ft/s) was the height of the water decreasing when its height was 16 ft? ft/s
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