For a traffic light, we are designing a 3-bit binary counter with D flip-flops that counts from 0 to 7 and back to 0 and repeats. The circuit also has 3 outputs: G (for green light), R (for red light) and Y (for yellow light).The green light is on (G=1) when the counter is at states: 0, 1, 2 and 3 and it is off (G=0) otherwise The yellow light is on (Y=1) when the counter is at state 4 and it is off (Y=0) otherwiseThe red light is on (R=1) when the counter is at states: 5, 6, and 7 and it is off (R=0) otherwise. Note that the circuit has no input.D. Implement the circuit. Solution :-) stale diagram® state table0 -8Present state101(010givenatgach state the o/pwereBstate Table :outrutsGYRD2 DI DoNent stateA' e'c'Present stateA BC100100O 10100O 10O 11100100101o OI☺ 0o00 D2, D,, DoTeali'sed uung Erutation table forayeD- JliptlopQnk-map soluing tor outpuli:BC1110Y = ABE(from state table )이。R: 00 0110R= AC+ ABK- mapSolving dor D- Hlipflops:ACABBC10P BC0011PĀBC01(1)1)JATABD2 =ĀBC4 AB + A TBCBEP, - Bc + BēDo:-BC0110DI =1/BTDo = BT t BīDo = CAll theequations dor outputi , Y, R and De, Pu PoHliptlop ip's are deviveoluing K- map solving .

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Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

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For a traffic light, we are designing a 3-bit binary counter with D flip-flops that counts from 0 to 7 and back to 0 and repeats. The circuit also has 3 outputs: G (for green light), R (for red light) and Y (for yellow light).
The green light is on (G=1) when the counter is at states: 0, 1, 2 and 3 and it is off (G=0) otherwise The yellow light is on (Y=1) when the counter is at state 4 and it is off (Y=0) otherwise
The red light is on (R=1) when the counter is at states: 5, 6, and 7 and it is off (R=0) otherwise. Note that the circuit has no input.
D. Implement the circuit.

Solution :-
) stale diagram
® state table
0 -8
Present state
101
(010
given
at
gach state the o/p
were
B
state Table :
outruts
GYR
D2 DI Do
Nent state
A' e'c'
Present state
A BC
100
100
O 10
100
O 10
O 11
100
100
101
o OI
☺ 0o
00

D2, D,, Do
Teali'sed uung Erutation table for
aye
D- Jliptlop
Qn
k-map soluing tor outpuli:
BC
11
10
Y = ABE
(from state table )
이。
R: 00 01
10
R= AC+ AB
K- map
Solving dor D- Hlipflops:
AC
AB
BC
10
P BC
00
11
PĀBC
01
(1)
1)
JAT
AB
D2 =
ĀBC4 AB + A T
BC
BE
P, - Bc + Bē
Do:-
BC
01
10
DI =
1/
BT
Do = BT t Bī
Do = C
All the
equations dor outputi , Y, R and De, Pu Po
Hliptlop ip's are deviveol
uing K- map solving .

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