Flame Atomic Absorption Spectroscopy (FAAS) method is selected due to its wide applicability for metal ion analysis in drinking water samples. Discuss how can we determine the concentration of selected heavy metals (Cu and Cr) in the unknown tap water sample.
Flame Atomic Absorption Spectroscopy (FAAS) method is selected due to its wide applicability for metal ion analysis in drinking water samples. Discuss how can we determine the concentration of selected heavy metals (Cu and Cr) in the unknown tap water sample.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Flame Atomic Absorption Spectroscopy (FAAS) method is selected due to its wide applicability for metal ion analysis in drinking water samples.
Discuss how can we determine the concentration of selected heavy metals (Cu and Cr) in the unknown tap water sample.
![Cu standard
Mean Absorbance
1
0.0521
2
0.1012
3
0.1577
4
0.2120
5
0.2685
Unknown
0.1666
0.3
v = 0.0544x - 0.0048
R² = 0.9994
0.25
0.2
0.15
0.1
0.05
1
2
3
[Cu]
The equation of the curve is y = 0.0544x - 0.0048 where y is absorbance and x = [Cu].
For unknown y = 0.1666
So,
0.1666 = 0.0544x - 0.0048
x = 3.150
So,
[Cu] in unknown = 3.150 ppm
Absorbance](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F27f8c9eb-5092-4cb1-874d-6b2c63b34b3c%2F832c9b48-96ed-47c6-9b77-c3f844de1fec%2Ffgnylm_processed.png&w=3840&q=75)
Transcribed Image Text:Cu standard
Mean Absorbance
1
0.0521
2
0.1012
3
0.1577
4
0.2120
5
0.2685
Unknown
0.1666
0.3
v = 0.0544x - 0.0048
R² = 0.9994
0.25
0.2
0.15
0.1
0.05
1
2
3
[Cu]
The equation of the curve is y = 0.0544x - 0.0048 where y is absorbance and x = [Cu].
For unknown y = 0.1666
So,
0.1666 = 0.0544x - 0.0048
x = 3.150
So,
[Cu] in unknown = 3.150 ppm
Absorbance
![Cr
Absorbance
0.0421
2
0.0779
3
0.1041
0.1370
5
0.1647
Unknown
0.0493
0.18
y = 0.0304x+0.0139,
R² = 0.9979
0.16
0.14
0.12
0.1
0.08
0.06
0.04
0.02
4.
6.
[Cu]
[Cr]
The equation of the curve is y= 0.0304x + 0.0139.
For unknown y= 0.0493
So,
0.0493 = 0.0304x +0.0139
x = 1.164
So,
[Cr] in unknown = 1.164 ppm
Absorbance](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F27f8c9eb-5092-4cb1-874d-6b2c63b34b3c%2F832c9b48-96ed-47c6-9b77-c3f844de1fec%2Ffem5vhc_processed.png&w=3840&q=75)
Transcribed Image Text:Cr
Absorbance
0.0421
2
0.0779
3
0.1041
0.1370
5
0.1647
Unknown
0.0493
0.18
y = 0.0304x+0.0139,
R² = 0.9979
0.16
0.14
0.12
0.1
0.08
0.06
0.04
0.02
4.
6.
[Cu]
[Cr]
The equation of the curve is y= 0.0304x + 0.0139.
For unknown y= 0.0493
So,
0.0493 = 0.0304x +0.0139
x = 1.164
So,
[Cr] in unknown = 1.164 ppm
Absorbance
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