Five thousand kg of steel containing 8% nickel is to be made by mixing a steel containing 14% with another steel containing 6% nickel. How much of the steel containing 6% nickel is needed? What mathematical equation would represent the problem? Let x be the amount of steel needed.
Five thousand kg of steel containing 8% nickel is to be made by mixing a steel containing 14% with another steel containing 6% nickel. How much of the steel containing 6% nickel is needed? What mathematical equation would represent the problem? Let x be the amount of steel needed.
Chapter2: Equations And Inequalities
Section2.3: Models And Applications
Problem 22SE: A chemistry teacher needs to mix a 30% salt solution with a 70% salt solution to make 20 qt of a 40%...
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Transcribed Image Text:Five thousand kg of steel containing 8% nickel is to be made
by mixing a steel containing 14% with another steel
containing 6% nickel. How much of the steel containing 6%
nickel is needed?
What mathematical equation would represent the problem?
Let x be the amount of steel needed.
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