Five moles of gas initially at a pressure of 2.00 atm and a volume of 0.300 L has internal energy equal to 91.0 J. In its final state, the gas is at a pressure of 1.50 atm and a volume of 0.800 L, and its internal energy equals 182 J. P (atm) 2.00 B A 1.50 F V (liters) 0.300 0.800 (a) For the paths IAF, IBF, and IF in the figure above, calculate the work done on the gas. W IAF = W = IBF W = IF J (b) For the paths IAF, IBF, and IF in the figure above, calculate the net energy transferred to the gas by heat in the process. QIAF = QIBF QIF = J J J

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Five moles of gas initially at a pressure of 2.00 atm and a volume of 0.300 L has internal energy equal to 91.0 J. In its final
state, the gas is at a pressure of 1.50 atm and a volume of 0.800 L, and its internal energy equals 182 J.
P (atm)
2.00
B
A
1.50
F
V (liters)
0.300
0.800
(a) For the paths IAF, IBF, and IF in the figure above, calculate the work done on the gas.
W
IAF =
W =
IBF
W =
IF
J
(b) For the paths IAF, IBF, and IF in the figure above, calculate the net energy transferred to the gas by heat in the
process.
QIAF =
QIBF
QIF
=
J
J
J
Transcribed Image Text:Five moles of gas initially at a pressure of 2.00 atm and a volume of 0.300 L has internal energy equal to 91.0 J. In its final state, the gas is at a pressure of 1.50 atm and a volume of 0.800 L, and its internal energy equals 182 J. P (atm) 2.00 B A 1.50 F V (liters) 0.300 0.800 (a) For the paths IAF, IBF, and IF in the figure above, calculate the work done on the gas. W IAF = W = IBF W = IF J (b) For the paths IAF, IBF, and IF in the figure above, calculate the net energy transferred to the gas by heat in the process. QIAF = QIBF QIF = J J J
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