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Fit y m 0=30% A) N-F cos 30 + mg cos30 = ma, lift B) N+F, cos 30 + mg cos 30 = ma, lift C) N+F cos30 – mg cos 30 = ma, та, D) N-F sin 30 + mg cos 30 lift %3D E) N+F sin 30 + mg cos30 = ma, lift

Fit y m 0=30% A) N-F cos 30 + mg cos30 = ma, lift B) N+F, cos 30 + mg cos 30 = ma, lift C) N+F cos30 – mg cos 30 = ma, та, D) N-F sin 30 + mg cos 30 lift %3D E) N+F sin 30 + mg cos30 = ma, lift

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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A block on an incline is partially supported by a vertical string as shown in the diagram. The coordinate system to be used for this problem is also shown, with the \( x \) and \( y \) axes tilted to align with the slope and normal. **Diagram Explanation:** - The block of mass \( m \) is placed on a 30° incline. - The block experiences a lifting force, \( F_{\text{lift}} \), directed upward. - The angle of the incline with respect to the horizontal is \( \theta = 30^\circ \). - The \( y \)-axis is perpendicular to the incline, and the \( x \)-axis is parallel to the incline. **Equation Options:** Identify the correct \( y \)-direction net force equation: A) \( N - F_{\text{lift}} \cos 30 + mg \cos 30 = ma_y \) B) \( N + F_{\text{lift}} \cos 30 + mg \cos 30 = ma_y \) C) \( N + F_{\text{lift}} \cos 30 - mg \cos 30 = ma_y \) D) \( N - F_{\text{lift}} \sin 30 + mg \cos 30 = ma_y \) E) \( N + F_{\text{lift}} \sin 30 + mg \cos 30 = ma_y \) F) \( N + F_{\text{lift}} \sin 30 - mg \cos 30 = ma_y \) **Question:** Which of the following choices correctly shows the \( y \)-direction \( F_{\text{net}} = ma \) equation?
Transcribed Image Text:A block on an incline is partially supported by a vertical string as shown in the diagram. The coordinate system to be used for this problem is also shown, with the \( x \) and \( y \) axes tilted to align with the slope and normal. **Diagram Explanation:** - The block of mass \( m \) is placed on a 30° incline. - The block experiences a lifting force, \( F_{\text{lift}} \), directed upward. - The angle of the incline with respect to the horizontal is \( \theta = 30^\circ \). - The \( y \)-axis is perpendicular to the incline, and the \( x \)-axis is parallel to the incline. **Equation Options:** Identify the correct \( y \)-direction net force equation: A) \( N - F_{\text{lift}} \cos 30 + mg \cos 30 = ma_y \) B) \( N + F_{\text{lift}} \cos 30 + mg \cos 30 = ma_y \) C) \( N + F_{\text{lift}} \cos 30 - mg \cos 30 = ma_y \) D) \( N - F_{\text{lift}} \sin 30 + mg \cos 30 = ma_y \) E) \( N + F_{\text{lift}} \sin 30 + mg \cos 30 = ma_y \) F) \( N + F_{\text{lift}} \sin 30 - mg \cos 30 = ma_y \) **Question:** Which of the following choices correctly shows the \( y \)-direction \( F_{\text{net}} = ma \) equation?
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