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fischer esterification:  5.4mL of isopentyl alcohol, molar mass 88.15g/mol:   8.5mL of acetic acid, molar mass 60.05 g/mol: Experimental final product(Isopentyl acetate) I got: 3.10g.   1.Calculate for theretical yield. 2.Percentage yield 3. % recovery.

fischer esterification:  5.4mL of isopentyl alcohol, molar mass 88.15g/mol:   8.5mL of acetic acid, molar mass 60.05 g/mol: Experimental final product(Isopentyl acetate) I got: 3.10g.   1.Calculate for theretical yield. 2.Percentage yield 3. % recovery.

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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fischer esterification:

 5.4mL of isopentyl alcohol, molar mass 88.15g/mol: 

 8.5mL of acetic acid, molar mass 60.05 g/mol:

Experimental final product(Isopentyl acetate) I got: 3.10g.  

1.Calculate for theretical yield.

2.Percentage yield

3. % recovery.

| Result : Reagent and product's Data Table Quantity Substance Isopentyl Alcohol 5.4ml Acetic acid Product: Isopentyl acetate Theoretical yield: 8.5mL 3.10g Molar mass (g/mol) 88.15 60.05 130.19 Boiling point Acetic Acid: 8.925g x (1mol/60.05g) = 0.148 mol Isopentyl Alcohol: 4.20g x (1oml/88.15g) = 0.0476 mol Limiting reagent: Isopentyl alcohol (smallest mole) 130 142 Density (g/ml) 0.809 1.049 0.876
Transcribed Image Text:| Result : Reagent and product's Data Table Quantity Substance Isopentyl Alcohol 5.4ml Acetic acid Product: Isopentyl acetate Theoretical yield: 8.5mL 3.10g Molar mass (g/mol) 88.15 60.05 130.19 Boiling point Acetic Acid: 8.925g x (1mol/60.05g) = 0.148 mol Isopentyl Alcohol: 4.20g x (1oml/88.15g) = 0.0476 mol Limiting reagent: Isopentyl alcohol (smallest mole) 130 142 Density (g/ml) 0.809 1.049 0.876
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