First trial of titration Initial level of 1.0 M NaOH Final level of 1.0 M NaOH (endpoint) Volume of 1.0 M NaOH added G.OIL Calculate the no. of moles of 1.0 M NaOH: Corresponding moles of acid (from reaction stoichiometry) Concentration (molarity) of acid: Second trial of titration Initial level of 1.0 M NaOH Final level of 1.0 M NaOH (endpoint) Volume of 1.0 M NaOH added Calculate the no. of moles of 1.0 M NaOH: Corresponding moles of acid (from reaction stoichiometry) Concentration (molarity) of acid: The average molarity of the acid from trials 1 and 2= 0 10 10-0 =10ml 0.0l moles 0.01 moles 0.01 0.05 = 0.2M O 11 11-0=11 0.011 moles .01 .05 0.ollmoles = 0.22M

First trial of titration Initial level of 1.0 M NaOH Final level of 1.0 M NaOH (endpoint) Volume of 1.0 M NaOH added G.OIL Calculate the no. of moles of 1.0 M NaOH: Corresponding moles of acid (from reaction stoichiometry) Concentration (molarity) of acid: Second trial of titration Initial level of 1.0 M NaOH Final level of 1.0 M NaOH (endpoint) Volume of 1.0 M NaOH added Calculate the no. of moles of 1.0 M NaOH: Corresponding moles of acid (from reaction stoichiometry) Concentration (molarity) of acid: The average molarity of the acid from trials 1 and 2= 0 10 10-0 =10ml 0.0l moles 0.01 moles 0.01 0.05 = 0.2M O 11 11-0=11 0.011 moles .01 .05 0.ollmoles = 0.22M

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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