First prove that triangles are congruent, then use CPCTC. H K Given: Prove: LFHG = LGFH O LGFH = LJHK 41 42 O LG = LJ Given that 21 and 22 are right

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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First, prove that triangles are congruent, then use CPCTC.

![Diagram of triangles](https://example.com/triangle-diagram)

Given:
- \( \angle 1 \) and \( \angle 2 \) are right angles.
- \( H \) is the midpoint of \( \overline{FK} \).

To Prove:
- \( \overline{FG} \cong \overline{HJ} \)

### Steps for Proof:

1. **Identifying Right Angles**:
   Given that \( \angle 1 \) and \( \angle 2 \) are right angles, the following statement holds because all right angles are congruent:
   - \( \angle 1 \cong \angle 2 \)

   \(\bigcirc\) \( \angle GFH \cong \angle LJK \)

2. **Midpoint Theorem**:
   Given that \( H \) is the midpoint of \( \overline{FK} \), the following statement holds because the midpoint forms two congruent segments:
   - \( \overline{FH} \cong \overline{HK} \)

   \(\bigcirc\) \( \overline{FH} \cong \overline{HK} \)

3. **Corresponding Angles**:
   Given \( \overline{FG} \parallel \overline{HJ} \), the following statement holds because lines cut by a transversal have congruent corresponding angles:
   - \( \angle GFH \cong \angle LJK \)

   \(\bigcirc\) \( \angle GFH \cong \angle LJK \)

4. **Applying ASA (Angle-Side-Angle)**:
   Therefore, by the reason ASA, the next-to-last statement of the proof is the following:
   - \( \triangle GFH \cong \triangle LJK \)

   \(\bigcirc\) \( \triangle GFH \cong \triangle LJK \)

5. **Using CPCTC (Corresponding Parts of Congruent Triangles are Congruent)**:
   Finally, by the reason CPCTC, the last statement of the proof is the following:
   - \( \overline{FG} \cong \overline{HJ} \)

   \(\bigcirc\) \( \overline{FG} \cong \overline
Transcribed Image Text:First, prove that triangles are congruent, then use CPCTC. ![Diagram of triangles](https://example.com/triangle-diagram) Given: - \( \angle 1 \) and \( \angle 2 \) are right angles. - \( H \) is the midpoint of \( \overline{FK} \). To Prove: - \( \overline{FG} \cong \overline{HJ} \) ### Steps for Proof: 1. **Identifying Right Angles**: Given that \( \angle 1 \) and \( \angle 2 \) are right angles, the following statement holds because all right angles are congruent: - \( \angle 1 \cong \angle 2 \) \(\bigcirc\) \( \angle GFH \cong \angle LJK \) 2. **Midpoint Theorem**: Given that \( H \) is the midpoint of \( \overline{FK} \), the following statement holds because the midpoint forms two congruent segments: - \( \overline{FH} \cong \overline{HK} \) \(\bigcirc\) \( \overline{FH} \cong \overline{HK} \) 3. **Corresponding Angles**: Given \( \overline{FG} \parallel \overline{HJ} \), the following statement holds because lines cut by a transversal have congruent corresponding angles: - \( \angle GFH \cong \angle LJK \) \(\bigcirc\) \( \angle GFH \cong \angle LJK \) 4. **Applying ASA (Angle-Side-Angle)**: Therefore, by the reason ASA, the next-to-last statement of the proof is the following: - \( \triangle GFH \cong \triangle LJK \) \(\bigcirc\) \( \triangle GFH \cong \triangle LJK \) 5. **Using CPCTC (Corresponding Parts of Congruent Triangles are Congruent)**: Finally, by the reason CPCTC, the last statement of the proof is the following: - \( \overline{FG} \cong \overline{HJ} \) \(\bigcirc\) \( \overline{FG} \cong \overline
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