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First pic the question Second pic i did not understand step 3

First pic the question Second pic i did not understand step 3

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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First pic the question Second pic i did not understand step 3
The magnetic circuit shown in the figure has two windings and two air gaps. The core can be assumed to be of infinite permeability. dimensions are indicated in the Core 00 Asca A The core Ara A N, ms self- figure. inductances of windings I and2 and the mutual inductance Find the Ny turas between the windings. Lu N. I. Req NI2. Reqa Rgill Rgz " O, - N.I, (Roi +Rs) N. N, 1, IRSI +Rs) I, Ps, 92 Lu Mダ。 .. NI Reg • Reg - P N. NE NI Ro Ln ス N, I N. NI, I, N2NI L12= Rg2
Transcribed Image Text:The magnetic circuit shown in the figure has two windings and two air gaps. The core can be assumed to be of infinite permeability. dimensions are indicated in the Core 00 Asca A The core Ara A N, ms self- figure. inductances of windings I and2 and the mutual inductance Find the Ny turas between the windings. Lu N. I. Req NI2. Reqa Rgill Rgz " O, - N.I, (Roi +Rs) N. N, 1, IRSI +Rs) I, Ps, 92 Lu Mダ。 .. NI Reg • Reg - P N. NE NI Ro Ln ス N, I N. NI, I, N2NI L12= Rg2
5:08 4 ONI, - is shostefaruit and Rg, is not sequiael at winding-2 side Rg2 : Reg, = Rg 2 .. $2 = N2 I2 Rg2 substituti p2 in O,> L22= N2 x N2 Iz I2 Rg2 Rg2 .. self Inductomce at winding-2 is L22= N,2 wheoje N2= Numbey of tuoms at winding-2 K9, > Reluc tance at gap-2 Step3 c) Mutual Induct amce Betuoe en the winding-) & winding-2 42= N2 020 Il But i2 = NII Rgz put O in0 > 412= 2 x Ni Il Il La mutual Inductamce Rg2 > L12 = NIN2
Transcribed Image Text:5:08 4 ONI, - is shostefaruit and Rg, is not sequiael at winding-2 side Rg2 : Reg, = Rg 2 .. $2 = N2 I2 Rg2 substituti p2 in O,> L22= N2 x N2 Iz I2 Rg2 Rg2 .. self Inductomce at winding-2 is L22= N,2 wheoje N2= Numbey of tuoms at winding-2 K9, > Reluc tance at gap-2 Step3 c) Mutual Induct amce Betuoe en the winding-) & winding-2 42= N2 020 Il But i2 = NII Rgz put O in0 > 412= 2 x Ni Il Il La mutual Inductamce Rg2 > L12 = NIN2
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