く>docs.google.com> Sh..> Co..> Do.> Co..B Th...[S..W w...C Si..m HB...X AL...htt...E Alg 2 -..Me...Al...Yo...Fireworks Displayh(10,72)(10,50(0,22)(0,0)Time (seconds)(20,0)(22,0)You are part of a fireworks crew assembling a local fireworks display. There aretwo parts to the fireworks platforms: one part is on the ground and the other partis on top of a building. You launch two fireworks. One from the ground and onefrom the top of the building. The path of the fireworks are in the above graph.1.) What is the equation, in standard form, of the path of firework #1? *(Standard Form: y= ax? + bx + c )у-1/2x^2+2.) What is the equation, in vertex form, of the path of firework #2? *Height (yards)BuildingFirew#2Firework #1 く>docs.google.com> Sh..> Co..> Do.> Co..B Th...W w...C Si..m HB...X AL...htt...E Alg 2 -..IS...Me...Al...Yo...(0,0)Time (seconds)(20,0)(22,0)You are part of a fireworks crew assembling a local fireworks display. There aretwo parts to the fireworks platforms: one part is on the ground and the other partis on top of a building. You launch two fireworks. One from the ground and onefrom the top of the building. The path of the fireworks are in the above graph.1.) What is the equation, in standard form, of the path of firework #1? *(Standard Form: y= ax + bx + c)у-1/2x^2+2.) What is the equation, in vertex form, of the path of firework #2? *Vertex Form: y = a(x – h)² + kYour answer3.) What are the domain and range of firework #1? *Your answerBuildingFirework

Given: The path of the fireworks is parabola.Let, The equation of the path of the firework#1 y=ax2+bx+c ⋯⋯⋯⋯⋯⋯ 1Path is passing through point 0,0. so, it satisfy the equation 10=a0+b0+cc=0It is also passing through the point 10,50. So,50=a102+b10+c50=100a+10b+0100a+10b=5010a+b=5 ⋯⋯⋯⋯⋯⋯⋯⋯ 2It is also passing through the point 20,0. So0=a202+b20+c0=400a+20b+0400a+20b=020a+b=0 ⋯⋯⋯⋯⋯⋯⋯⋯⋯ 3Subtracting equation 2 from equation 1,20a+b-10a+b=0-520a+b-10a-b=-510a=-5a=-510a=-12Substitute the value of a in equation 2,10-12+b=5-5+b=5b=5+5b=10Substituting the values of a, b and c in equation 1, we gety=-12x2+10x+0y=-12x2+10x Therefore, In standard form, the equation of the path of firework#1 is y=-12x2+10xThe equation of the path of firework#2 in vertex form can be written as: y=ax-h2+k ⋯⋯⋯⋯⋯ 4where h,k is the vertex of the path From the given graph, the vertex of the path of firework#2 is (10,72). So, h = 10 k = 72 Substitute the value of h and k in equation 4, y=ax-102+72 ⋯⋯⋯⋯⋯⋯ 5Path is passing through the point 22,0. So,0=a22-102+720=a122+720=144a+72144a=-72a=-72144a=-12Substitute the value of a in equation 5,y=-12x-102+72 Therefore, In vertex form, the equation of the path of firework#2 is y=-12x-102+72Domain: The set of input values on x-axis is domain of the function. Range: The set of all output values on y-axis is range of the function. Therefore, The domain of the firework#1 is 0,20 The range of the firework#1 is 0,50

Math

Algebra

Fireworks Display (10,72) (10,50 (0,22) (0.0) Time (seconds) (20,0) (22.0) You are part of a fireworks crew assembling a local fireworks display. There are two parts to the fireworks platforms: one part is on the ground and the other part is on top of a bulding. You launch two fireworks. One from the ground and one from the top of the building. The path of the fireworkis are in the above graph. 1.) What is the equation, in standard form, of the path of firework #1? * (Standard Form: y = ax² + bx + c ) y=-1/2x^2+ Height (yards) Building Firework #2 Firework #1

Fireworks Display (10,72) (10,50 (0,22) (0.0) Time (seconds) (20,0) (22.0) You are part of a fireworks crew assembling a local fireworks display. There are two parts to the fireworks platforms: one part is on the ground and the other part is on top of a bulding. You launch two fireworks. One from the ground and one from the top of the building. The path of the fireworkis are in the above graph. 1.) What is the equation, in standard form, of the path of firework #1? * (Standard Form: y = ax² + bx + c ) y=-1/2x^2+ Height (yards) Building Firework #2 Firework #1

Algebra and Trigonometry (6th Edition)

6th Edition

ISBN:9780134463216

Author:Robert F. Blitzer

Publisher:Robert F. Blitzer

ChapterP: Prerequisites: Fundamental Concepts Of Algebra

Section: Chapter Questions

Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...

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Question

く>
docs.google.com
> Sh..
> Co..
> Do.
> Co..
B Th...
[S..
W w...
C Si..
m HB...
X AL...
htt...
E Alg 2 -..
Me...
Al...
Yo...
Fireworks Display
h
(10,72)
(10,50
(0,22)
(0,0)
Time (seconds)
(20,0)
(22,0)
You are part of a fireworks crew assembling a local fireworks display. There are
two parts to the fireworks platforms: one part is on the ground and the other part
is on top of a building. You launch two fireworks. One from the ground and one
from the top of the building. The path of the fireworks are in the above graph.
1.) What is the equation, in standard form, of the path of firework #1? *
(Standard Form: y= ax? + bx + c )
у-1/2x^2+
2.) What is the equation, in vertex form, of the path of firework #2? *
Height (yards)
Building
Firew
#2
Firework #1

く>
docs.google.com
> Sh..
> Co..
> Do.
> Co..
B Th...
W w...
C Si..
m HB...
X AL...
htt...
E Alg 2 -..
IS...
Me...
Al...
Yo...
(0,0)
Time (seconds)
(20,0)
(22,0)
You are part of a fireworks crew assembling a local fireworks display. There are
two parts to the fireworks platforms: one part is on the ground and the other part
is on top of a building. You launch two fireworks. One from the ground and one
from the top of the building. The path of the fireworks are in the above graph.
1.) What is the equation, in standard form, of the path of firework #1? *
(Standard Form: y= ax + bx + c
)
у-1/2x^2+
2.) What is the equation, in vertex form, of the path of firework #2? *
Vertex Form: y = a(x – h)² + k
Your answer
3.) What are the domain and range of firework #1? *
Your answer
Building
Firework

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