Finding an Inverse Function InformallyIn Exercises 7–14, find the inverse function off informally. Verify that f( f −1(x)) = x andf −1( f(x)) = x.7. f(x) = 6x 8. f(x) = 13x9. f(x) = 3x + 1 10. f(x) = x − 3211. f(x) = x2 − 4, x ≥ 012. f(x) = x2 + 2, x ≥ 013. f(x) = x3 + 114. f(x) = x54

Finding an Inverse Function InformallyIn Exercises 7–14, find the inverse function off informally. Verify that f( f −1(x)) = x andf −1( f(x)) = x.7. f(x) = 6x 8. f(x) = 13x9. f(x) = 3x + 1 10. f(x) = x − 3211. f(x) = x2 − 4, x ≥ 012. f(x) = x2 + 2, x ≥ 013. f(x) = x3 + 114. f(x) = x54

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter3: Functions And Graphs

Section3.5: Graphs Of Functions

Problem 36E

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Concept explainers

Limits

When it comes to calculus, limits are considered to be a very important topic of discussion. The main importance of limit lies in expressing the value of a function as it gets closer to a certain value. Also, limits can help you to understand other topics, such as continuity and differentiability better. In a broader sense, every calculus notion is a limit. Other branches of calculus have also been derived from limits.

Question

Finding an Inverse Function Informally
In Exercises 7–14, find the inverse function of
f informally. Verify that f( f −1(x)) = x and
f −1( f(x)) = x.
7. f(x) = 6x 8. f(x) = 1
3
x
9. f(x) = 3x + 1 10. f(x) = x − 3
2
11. f(x) = x2 − 4, x ≥ 0
12. f(x) = x2 + 2, x ≥ 0
13. f(x) = x3 + 1
14. f(x) = x5
4

Expression, rule, or law that gives the relationship between an independent variable and dependent variable. Some important types of functions are injective function, surjective function, polynomial function, and inverse function.

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