Find Z test proportion 2. In Hospital A, tracheotomy had been done in 60 patients out of 150 while in the other Hospital B it was done in 50 out of 150. Find if the difference observed in the two Hospitals is by chance or due to some influence. Find the overall sample proportion: 60 P1 = nl = 150 150 50 P2 = , n2 = 150 150 Find the overall sample proportion X1 + X2 = 60 + 50 %3D n + n2 150 + 150 ,1-p Null Hypothesis H: There is no significant difference in the tracheotomy in both hospitals H: There is a significant difference in the tracheotomy in both hospitals • We Use a 5% alpha level. • Ztest statistics is given as: Page 3 of 4 • Z = %3D P1-P2 x( 150 150 Z= • The critical value associated with a 5% alpha level is1.96. • Analysis: Computed value is than the critical value 1.9 • Decision: Ho Conclusion: There is ------------.- in the tracheotomy rate at 95% significance level between Hospital A and Hospital B

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Find Z test proportion
2. In Hospital A, tracheotomy had been done in 60 patients out of 150 while
in the other Hospital B it was done in 50 out of 150. Find if the difference
observed in the two Hospitals is by chance or due to some influence.
Find the overall sample proportion _:
60
P, =
150
nl = 150
50
p, =
150
- , n2 = 150
Find the overall sample proportion
X1 + X2
60 + 50
%3D
n1 + n2
150 + 150
,1-p
Null Hypothesis
H: There is no significant difference in the tracheotomy in both hospitals
H: There is a significant difference
e tracheotomy in both hospitals
We Use a 5% alpha level.
• Ztest statistics is given as:
Page 3 of 4
P1-P2
%3D
%3D
x(
150
Z=
The critical value associated with a 5% alpha level is1.96.
• Analysis: Computed value is
than the critical value 1.9
• Decision: Ho
Conclusion: There is - ------ in the tracheotomy rate at 95%
significance level between Hospital A and Hospital B
Transcribed Image Text:Find Z test proportion 2. In Hospital A, tracheotomy had been done in 60 patients out of 150 while in the other Hospital B it was done in 50 out of 150. Find if the difference observed in the two Hospitals is by chance or due to some influence. Find the overall sample proportion _: 60 P, = 150 nl = 150 50 p, = 150 - , n2 = 150 Find the overall sample proportion X1 + X2 60 + 50 %3D n1 + n2 150 + 150 ,1-p Null Hypothesis H: There is no significant difference in the tracheotomy in both hospitals H: There is a significant difference e tracheotomy in both hospitals We Use a 5% alpha level. • Ztest statistics is given as: Page 3 of 4 P1-P2 %3D %3D x( 150 Z= The critical value associated with a 5% alpha level is1.96. • Analysis: Computed value is than the critical value 1.9 • Decision: Ho Conclusion: There is - ------ in the tracheotomy rate at 95% significance level between Hospital A and Hospital B
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