Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![The problem presented is to find the derivative \( y' \) of the given function:
\[ y = \left(\frac{1}{x} + 3 \right) \left( x - \frac{1}{x} + 3 \right) \]
The options for the first derivative are:
- **A.** \(-\frac{1}{x^3} - 3\)
- **B.** \(\frac{1}{x^3} + 3\)
- **C.** \(-\frac{2}{x^3} - 3\)
- **D.** \(\frac{2}{x^3} + 3\)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F65e9754d-e7bf-4951-a913-18b478a6d2d4%2F33c1102e-884e-4a0a-952c-6f43be4734d8%2F4lakolc_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The problem presented is to find the derivative \( y' \) of the given function:
\[ y = \left(\frac{1}{x} + 3 \right) \left( x - \frac{1}{x} + 3 \right) \]
The options for the first derivative are:
- **A.** \(-\frac{1}{x^3} - 3\)
- **B.** \(\frac{1}{x^3} + 3\)
- **C.** \(-\frac{2}{x^3} - 3\)
- **D.** \(\frac{2}{x^3} + 3\)
Expert Solution
Step 1
Given:-
y=((1/x) +3) (x-(1/x) +3)
To find:-
y'
Step by step
Solved in 3 steps with 1 images
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