Find y': COS X y = 1-sin x O y' = sin² -sin x-cos² x (1-sin x)²

Q: Find f. f ''(?) = sin(?) + cos(?),    f(0) = 4,    f '(0) = 2

A: f''(x)= sin(x) + cos(x) , f(0)=4 ,f'(0) = 2

Q: العنوان solle Le sin²(3x) cos²(sx) dx /1 8 tan'x dx で CIC

A: (1): Step 1:Step 2: Step 3:Step 4: (2): Step 1:Step 2:Step 3:Step 4:

Q: Find of an

A: We are asked to find y'

Q: 9. f(0) = (0 cos 0) sin 0

A:

Q: 3 sin x If f(x) then 2 + cos x f'(x) =

A:

Q: Find f'a) for f(x)= =Sinx 1- Cos X %3D

A: We have to find the derivative of the given function.

Q: Find y' where y where y = 10 sin-1 (cos (21 z)) - tan C BARANG (18 r)

A: Given: Now,             y'=10arcsincos21x-arctan18x'     =10arcsincos21x' -arctan18x'…

Q: cos(4x) cos(2x) sin(4x) sec(2x) 12. Verify: - sin(2x)

A: cos(2x ) =cos2(x)-sin2(x) = 2cos2(x)-1 =1-2sin2(x) sin(2x) = 2sin(x) cos(x)

Q: Let f(z) = (9 sin z + 2 cosz)tan¹z

A:

Q: Find f'(x) where f(x) sin(cos(4x2 +1))

A: Consider the given function

Q: The derivative of y = 3cos(8x+6) is: 1. y' = 24 sin (8x+6) 2. y' = -24 sin (8x+6) 3. y' = -24 cos…

A:

Q: et f(x)=-11sin x+3 cos x f' (x)=?

A: f(x)=-11sin x+3 cos x this is given  we have to differentiate the function  dsinx/dx = cosx…

Q: Find the y'(0) when y = cos (sec²(2x))

A:

Q: Find f. f ''(?) = sin ? + cos ?,    f(0) = 1,    f '(0) = 3

A: