Find y as a function of a if y(0) = 1, y'(0) = 9, y" (0) = -191. y(r) = j y"-7y" -y + 7y=0,

Q: Find y as a function of a if y(0)2, y'(0) = 3, "(0) = -13. y(x) = y″ − 4y″ − y′ + 4y = 0,

A: Given a differential equation:initial conditions are:

Q: Find y as a function of if y(0) = 18, y'(0) = 28, y'(0) = 21. y(x) = y"-9y" + 20y = 24e,

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Q: Find y as a function of t if y(4) = 6, y (4) = 4. y = 121y" - 132y +36y = 0,

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Q: Find y as a function of x if x'y" + 5xy' + 4y = 0, y(1) = 9, y'(1) = -2. y =

A: Solution :-

Q: Find y as a function of x if x²y" +5xy - 12y = x², y(1) = −9, y(1) = 9. y=

A: We have to find as a function of .

Q: Find f, (2,0) if f(x,y) = 18x e Y. 1,(2.0) = %3D

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Q: Find y as a function of a if y"" - 12y" + 35y' = 24e", y(0) = 27, y'(0) = 11, y'(0) = 30. y(x) =

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Q: Find y as a function of a if y(0) = 19, y'(0) = 26, y" (0) = 14. y(x) = y"" - 10y" + 21y' = 48e²,

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Q: Find y as a function of a if y(1) = -4, y'(1) = -9. y x²y" + 2xy' - 6y = 0,

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Q: Find y as a function of a if y(1) = 8, y'(1) = 6. y = x²y" + 3xy' - 35y = 0,

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Q: Find y as a function of a if y(1)9, y'(1) = -5. y = x²y" - 15xy' + 64y = x²,

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Q: Find y as a function of a if y(0) = 6, y'(0) = 24, y"(0) = 108. y" + 36y' = 0,

A: y′′′+36y′=0y(0)=6,y′(0)=24,y′′(0)=108.The characteristic equation…

Q: Find y as a function of t if y(0) = 2, y'(0) = 5. y(t) = 100y" +9y = 0,

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Q: Find f, (x.y) if f(x.y)=x - 5xy- 4y2.

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Q: function of xx if

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Q: Find y as a function of if y(0) = 19, y'(0) = 19, y"(0) = 4, y"(0) = 0. y(x) = y(4) 4y" + 4y = 0,

A: y(4)−4y′′′+4y′′=0y(0)=19,y′(0)=19,y′′(0)=4,y′′′(0)=0

Q: find y as a function of x if y'" + 81y' - = 0 where y(0) = 1, y'(0) = 81, y"(0) = 324

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Q: Find y'' for y = 4+ or y= (4 + ³) ³. X y"=0 3 5

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Q: Find y as a function of a if y" - 3y" y + 3y = 0, y(0) = -7, y' (0) = -4, y" (0) = 9. y(x) =

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Q: Find y as a function of a if = y"-7y" +12y = 6e², y(0) = 24, y' (0) = 16, y" (0) = 27. y(x)=

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Q: Find a > 1 to express y = 3(2/9)x in the form y = 3(a−x)

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