Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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the first one i ask here says it is wrong so, i asked again
![**Problem:**
Find \( y' \) and \( y'' \) for the equation \( x^2 + 2xy - 3y^2 = 41 \). Simplify.
**Solution:**
For \( y' \):
- Derivative of the given equation with respect to \( x \) yields:
\[
y' = \frac{-2x - 2y}{2x - 6y}
\]
**Note:** There are links or buttons labeled "help (formulas)" that suggest assistance is available for formulas.
For \( y'' \):
- The second derivative \( y'' \) is not provided in the image, indicating a new calculation or formula is required.
**Assistance:**
- There are "help (formulas)" links suggesting additional resources or guides are available to assist with finding the derivatives.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd7dcbfcd-ec40-4419-b8e9-2a693a942e70%2Fde62468a-a945-410d-b970-2c257460cc5b%2Fo95qzal_processed.png&w=3840&q=75)
Transcribed Image Text:**Problem:**
Find \( y' \) and \( y'' \) for the equation \( x^2 + 2xy - 3y^2 = 41 \). Simplify.
**Solution:**
For \( y' \):
- Derivative of the given equation with respect to \( x \) yields:
\[
y' = \frac{-2x - 2y}{2x - 6y}
\]
**Note:** There are links or buttons labeled "help (formulas)" that suggest assistance is available for formulas.
For \( y'' \):
- The second derivative \( y'' \) is not provided in the image, indicating a new calculation or formula is required.
**Assistance:**
- There are "help (formulas)" links suggesting additional resources or guides are available to assist with finding the derivatives.
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