Find y' and the slope of the tangent line to the graph of (3x- 2y)° = 2y2 - 9 at the point (1,2).

Find an equation of the tangent line to the graph of the equation x + y – ex - Y = 5 at the point (3, 3). y =

Find y in terms of x. =x*(32-x)'. curve passes through (2,2) xp The solution is y =

How could I find the equation of the tangent line?

Calculate y" and y'''.      y = ex /x

Find y' and then find the slope of the tangent line at (4, 1600). Round the slope and y-intercept to 3 decimal place. y = (x² + 4x+8) ² y' = The tangent line at (4, 1600) is y = x +

Please help me with this question.