Find (x) and (8). (+)(x) = (x)= 104 (Simplify your answer.)

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ChapterP: Prerequisites: Fundamental Concepts Of Algebra
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Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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**Unit 3 HW 2.3: The Algebra of Functions**

Let \( f(x) = x^2 + 5x \) and \( g(x) = 9 - x \).

Find 
\[
\left( \frac{f}{g} \right)(x) \text{ and } \left( \frac{f}{g} \right)(8).
\]

\[
\left( \frac{f}{g} \right)(x) = 104 \quad (\text{Simplify your answer.})
\]
Transcribed Image Text:**Unit 3 HW 2.3: The Algebra of Functions** Let \( f(x) = x^2 + 5x \) and \( g(x) = 9 - x \). Find \[ \left( \frac{f}{g} \right)(x) \text{ and } \left( \frac{f}{g} \right)(8). \] \[ \left( \frac{f}{g} \right)(x) = 104 \quad (\text{Simplify your answer.}) \]
### The Algebra of Functions

Given two functions:
- \( f(x) = x^2 + 6x \)
- \( g(x) = 1 - x \)

We are tasked with finding:
- \( (f - g)(x) \)
- \( (f - g)(5) \)

#### Solution:

1. **Calculate \( (f - g)(x) \):**

   \[
   (f - g)(x) = f(x) - g(x)
   \]
   \[
   = (x^2 + 6x) - (1 - x)
   \]
   \[
   = x^2 + 6x - 1 + x
   \]
   \[
   = x^2 + 7x - 1
   \]

2. **Calculate \( (f - g)(5) \):**

   Substitute \( x = 5 \) into \( (f - g)(x) \):
   \[
   (f - g)(5) = 5^2 + 7(5) - 1
   \]
   \[
   = 25 + 35 - 1
   \]
   \[
   = 59
   \]

Thus, \( (f - g)(x) = x^2 + 7x - 1 \) and \( (f - g)(5) = 59 \).
Transcribed Image Text:### The Algebra of Functions Given two functions: - \( f(x) = x^2 + 6x \) - \( g(x) = 1 - x \) We are tasked with finding: - \( (f - g)(x) \) - \( (f - g)(5) \) #### Solution: 1. **Calculate \( (f - g)(x) \):** \[ (f - g)(x) = f(x) - g(x) \] \[ = (x^2 + 6x) - (1 - x) \] \[ = x^2 + 6x - 1 + x \] \[ = x^2 + 7x - 1 \] 2. **Calculate \( (f - g)(5) \):** Substitute \( x = 5 \) into \( (f - g)(x) \): \[ (f - g)(5) = 5^2 + 7(5) - 1 \] \[ = 25 + 35 - 1 \] \[ = 59 \] Thus, \( (f - g)(x) = x^2 + 7x - 1 \) and \( (f - g)(5) = 59 \).
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