Last edit was.e Arrange Tools Add-ons HelpBackgroundLayoutThemeTransition1|| | | | | I | IEFind x16 in.Show your work here.12 in.d speaker notes ge Tools Add-onsHelpLast edit was..BackgroundLayoutThemeTransitionFind xShow your work here.4.0 cm9.6 cmker notesC

Answered: Find x 16 in. Show your work here. 12…

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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e Arrange Tools Add-ons Help
Background
Layout
Theme
Transition
1|| | | | | I | IE
Find x
16 in.
Show your work here.
12 in.
d speaker notes

ge Tools Add-ons
Help
Last edit was..
Background
Layout
Theme
Transition
Find x
Show your work here.
4.0 cm
9.6 cm
ker notes
C

Expert Solution

Calculation:

Given height is 16 in. and base is 12 in.

To find x, Pythagoras theorem is used:

Pythagoras theorem says that in a right angled triangle ABC, the length of the hypotenuse is found by the square root of the sum of squares of the base and height of the right triangle.

That is: $c = \sqrt{a^{2} + b^{2}}$

where, c is the length of hypotenuse

a and b are lengths of base and height of a right angled triangle.

Now, in the given figure:

x is the hypotenuse,

length of base is 12 in. and height is 16 in.

So, x is found by:

$\begin{array}{rcl} x & = & \sqrt{16^{2} + 12^{2}} \\ = & \sqrt{400} \\ = & 20 \end{array}$

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