Find voltage across each of the 5 resistors. Find current through each of the 5 resistors. Find power through each of the 5 resistors. My attempt at the solution: I know that total voltage is 24V. I add 12+3+2 since they're in series which equals 17ohms, which reduces total number of resistors. Then I add the parallels: 1/17+1/33=50/561>>>561/50=11.2ohms, then I add remaining 5ohm resistor. 5+11.2=16.2ohms, which is total resistance. Total current would be 24/16.2=1.5A   Next I try to solve the following: Voltage across 5ohm resistor: 1.5*5=7.5V, which I know is correct. Voltage across 33ohm: 11.2*1.5=16.8V, which I know is correct. Voltage across 12, 3, and 2: I thought I was correct to do 11.2*1.5=16.8V (since 33 and 17 resistors both equal 11.2ohms), but according to my textbook, that answer is wrong and affects the results for power as well. Current through 5: 7.5/5=1.5A, which is correct. Current through 33: 16.8/33=0.51A, which is correct. Current through 12, 3, and 2: Again, I assume it's 16.8/17=0.99A, which is the only correct answer I got for these resistors. Power through 5: 7.5*1.5=11W, which is correct. Power through 33: 16.8*0.51=8.6W, which is correct. Power through 12, 3, and 2: 16.8/0.99=16.6W, which is wrong according to text. I just need help with the voltage and power steps for resistors 12, 3, and 2, if possible.

Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
icon
Related questions
icon
Concept explainers
Question
100%

Find voltage across each of the 5 resistors.

Find current through each of the 5 resistors.

Find power through each of the 5 resistors.

My attempt at the solution: I know that total voltage is 24V.

I add 12+3+2 since they're in series which equals 17ohms, which reduces total number of resistors.

Then I add the parallels: 1/17+1/33=50/561>>>561/50=11.2ohms, then I add remaining 5ohm resistor.

5+11.2=16.2ohms, which is total resistance. Total current would be 24/16.2=1.5A

 

Next I try to solve the following:

Voltage across 5ohm resistor: 1.5*5=7.5V, which I know is correct.

Voltage across 33ohm: 11.2*1.5=16.8V, which I know is correct.

Voltage across 12, 3, and 2: I thought I was correct to do 11.2*1.5=16.8V (since 33 and 17 resistors both equal 11.2ohms), but according to my textbook, that answer is wrong and affects the results for power as well.

Current through 5: 7.5/5=1.5A, which is correct.

Current through 33: 16.8/33=0.51A, which is correct.

Current through 12, 3, and 2: Again, I assume it's 16.8/17=0.99A, which is the only correct answer I got for these resistors.

Power through 5: 7.5*1.5=11W, which is correct.

Power through 33: 16.8*0.51=8.6W, which is correct.

Power through 12, 3, and 2: 16.8/0.99=16.6W, which is wrong according to text.

I just need help with the voltage and power steps for resistors 12, 3, and 2, if possible.

### Electrical Circuit Diagram

This diagram represents a basic electrical circuit with several components connected in different configurations. Below is a detailed description of the elements in this circuit:

#### Components:
1. **Voltage Source**:
   - The circuit includes a 24V voltage source denoted by a circle with a plus and minus sign, indicating the polarity.

2. **Resistors**:
   - There are five resistors in the circuit:
     - A 5-ohm resistor connected in series near the bottom left.
     - A 2-ohm resistor in series to the right of the 5-ohm resistor.
     - A 33-ohm resistor placed in parallel with the above two resistors.
     - A combination of a 12-ohm resistor and a 3-ohm resistor in series, together forming a branch parallel to the rest of the circuit.

#### Circuit Configuration:

- The circuit has a combination of series and parallel connections:
  - The 5-ohm and 2-ohm resistors are in series, resulting in their resistance values being summed.
  - This series combination is parallel to the 33-ohm resistor.
  - The parallel combination then connects to another series branch consisting of the 12-ohm and 3-ohm resistors.

This diagram is an example of how resistors can be arranged in circuits to achieve the desired resistance values and current distribution. Understanding these configurations is crucial for circuit analysis and design.
Transcribed Image Text:### Electrical Circuit Diagram This diagram represents a basic electrical circuit with several components connected in different configurations. Below is a detailed description of the elements in this circuit: #### Components: 1. **Voltage Source**: - The circuit includes a 24V voltage source denoted by a circle with a plus and minus sign, indicating the polarity. 2. **Resistors**: - There are five resistors in the circuit: - A 5-ohm resistor connected in series near the bottom left. - A 2-ohm resistor in series to the right of the 5-ohm resistor. - A 33-ohm resistor placed in parallel with the above two resistors. - A combination of a 12-ohm resistor and a 3-ohm resistor in series, together forming a branch parallel to the rest of the circuit. #### Circuit Configuration: - The circuit has a combination of series and parallel connections: - The 5-ohm and 2-ohm resistors are in series, resulting in their resistance values being summed. - This series combination is parallel to the 33-ohm resistor. - The parallel combination then connects to another series branch consisting of the 12-ohm and 3-ohm resistors. This diagram is an example of how resistors can be arranged in circuits to achieve the desired resistance values and current distribution. Understanding these configurations is crucial for circuit analysis and design.
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps

Blurred answer
Knowledge Booster
Protection System in Power Plant
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, electrical-engineering and related others by exploring similar questions and additional content below.
Recommended textbooks for you
Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
Electrical Engineering
ISBN:
9780133923605
Author:
Robert L. Boylestad
Publisher:
PEARSON
Delmar's Standard Textbook Of Electricity
Delmar's Standard Textbook Of Electricity
Electrical Engineering
ISBN:
9781337900348
Author:
Stephen L. Herman
Publisher:
Cengage Learning
Programmable Logic Controllers
Programmable Logic Controllers
Electrical Engineering
ISBN:
9780073373843
Author:
Frank D. Petruzella
Publisher:
McGraw-Hill Education
Fundamentals of Electric Circuits
Fundamentals of Electric Circuits
Electrical Engineering
ISBN:
9780078028229
Author:
Charles K Alexander, Matthew Sadiku
Publisher:
McGraw-Hill Education
Electric Circuits. (11th Edition)
Electric Circuits. (11th Edition)
Electrical Engineering
ISBN:
9780134746968
Author:
James W. Nilsson, Susan Riedel
Publisher:
PEARSON
Engineering Electromagnetics
Engineering Electromagnetics
Electrical Engineering
ISBN:
9780078028151
Author:
Hayt, William H. (william Hart), Jr, BUCK, John A.
Publisher:
Mcgraw-hill Education,