Your video analysis of the motion of a marble gives it position inframe 23 as(x23 , Y23) = (0.134 m, 0.120 m)and its position in frame 24 as(24 , Y24) = (0.102 m, 0.112 m).You estimate that you can measure the r and y positions withuncertainty ±0.003 m. The frame rate of the video is 30frames/s, which means the time interval between frames isAt = 0.033333 s. The uncertainty of the frame rate of a videocamera is VERY small. For the sake of this problem, use8(At) = 1 x 10 s. The mass of the marble is(2.031 0.001) x 10 2 kg. Find value of the y-component of the marble's velocityand its uncertainty.At0(-0.2 +0.1) m/sO(0.660 +0.127) m/s0(0.066 0.004) m/s3.70 0.01) m/s

Given that:y23=0.120 my24=0.112 m∆y=±0.003 m∆t=0.033333 sδ(∆t)=1×10-6 s

Answered: Find value of the y-component of the…

Find value of the y-component of the marble's velocity Yi+1 - Yi Vy and its uncertainty. At O(-0.2 + 0.1) m/s O(-0.660 +0.127) m/s O(-0.066 0.004) m/s O(3.70 0.01) /s.

Glencoe Physics: Principles and Problems, Student Edition

1st Edition

ISBN:9780078807213

Author:Paul W. Zitzewitz

Publisher:Paul W. Zitzewitz

Chapter2: Representing Motion

Section: Chapter Questions

Problem 48A

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