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Find V, when S=1.0+j0.5 p.u.

Find V, when S=1.0+j0.5 p.u.

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Two-Bus Example v (iteration number) V2 120° pu 1 0.9671-j0.0568 0.9624-j0.0553 3 0.9622-j0.0556 4 0.9622-j0.0556 Stop if Av,"|=|v.*) – v,"| < 6 S, = V,YV = -1.0– j0.5 p.u. (v+1) 2n n=1 V, = 0.9638Z- 3.3° p.u. Injection:+ V, = 1.020° p.u. consumption:- I12 = Yı2(V1 –V½) =1.0615Z164.2° p.u. I,0 = Y12V½ = j0.05 p.u. I, = I,0 + 1,2 S, = V,EYV =1.024+ j0.239 p.u. n=1 P = 102.4 MW(at a base of 100 MVA) Q = 239 MVar 74
Transcribed Image Text:Two-Bus Example v (iteration number) V2 120° pu 1 0.9671-j0.0568 0.9624-j0.0553 3 0.9622-j0.0556 4 0.9622-j0.0556 Stop if Av,"|=|v.*) – v,"| < 6 S, = V,YV = -1.0– j0.5 p.u. (v+1) 2n n=1 V, = 0.9638Z- 3.3° p.u. Injection:+ V, = 1.020° p.u. consumption:- I12 = Yı2(V1 –V½) =1.0615Z164.2° p.u. I,0 = Y12V½ = j0.05 p.u. I, = I,0 + 1,2 S, = V,EYV =1.024+ j0.239 p.u. n=1 P = 102.4 MW(at a base of 100 MVA) Q = 239 MVar 74
Two-Bus Example (G-S) 1 2 • Find V, when S=1.0+j0.5 p.u. SL 1 I12 712 = 0.02+j0.06 p.u. 2 IL 20 + Icap I10 Y10-j0.05 pu SL Vj=120° pu V2 Y20=j0.05 pu Yeap-j0.25 pu
Transcribed Image Text:Two-Bus Example (G-S) 1 2 • Find V, when S=1.0+j0.5 p.u. SL 1 I12 712 = 0.02+j0.06 p.u. 2 IL 20 + Icap I10 Y10-j0.05 pu SL Vj=120° pu V2 Y20=j0.05 pu Yeap-j0.25 pu
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