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Find v, assuming an ideal OpAmp. 8 Ω v2 16 Ω 12 Ω Vo + 7.5 V 24 Ω - + +

Find v, assuming an ideal OpAmp. 8 Ω v2 16 Ω 12 Ω Vo + 7.5 V 24 Ω - + +

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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**Title: Analysis of an Op-Amp Circuit** **Objective:** Find the output voltage \( v_o \) assuming an ideal operational amplifier (OpAmp). **Circuit Description:** - **Voltage Source:** 7.5 V - **Resistors:** - \(16 \, \Omega\) resistor between the voltage source and \( v_1 \) - \(24 \, \Omega\) resistor connected in parallel with the path between \( v_1 \) and ground - \(8 \, \Omega\) resistor connected to the non-inverting input of the OpAmp (\( v_2 \)) - \(12 \, \Omega\) resistor connected between the OpAmp output (\( v_o \)) and the inverting input **Op-Amp Configuration:** - The OpAmp is configured with feedback. - The non-inverting input (+) receives the voltage \( v_2 \) after the \(8 \, \Omega\) resistor. - The inverting input (-) is connected to \( v_1 \). **Graph/Diagram Explanation:** This circuit includes a voltage source, resistors, and an ideal OpAmp. The \(16 \, \Omega\), \(24 \, \Omega\), and \(8 \, \Omega\) resistors create a voltage divider that affects the voltage at \( v_1 \) and \( v_2 \). The OpAmp amplifies the difference between these inputs, resulting in the output voltage \( v_o \). The \(12 \, \Omega\) resistor is part of the feedback loop, influencing the gain and stability of the OpAmp. **Assumption:** The OpAmp is ideal, implying: - Infinite open-loop gain - Infinite input impedance - Zero output impedance **Objective:** Determine the value of \( v_o \).
Transcribed Image Text:**Title: Analysis of an Op-Amp Circuit** **Objective:** Find the output voltage \( v_o \) assuming an ideal operational amplifier (OpAmp). **Circuit Description:** - **Voltage Source:** 7.5 V - **Resistors:** - \(16 \, \Omega\) resistor between the voltage source and \( v_1 \) - \(24 \, \Omega\) resistor connected in parallel with the path between \( v_1 \) and ground - \(8 \, \Omega\) resistor connected to the non-inverting input of the OpAmp (\( v_2 \)) - \(12 \, \Omega\) resistor connected between the OpAmp output (\( v_o \)) and the inverting input **Op-Amp Configuration:** - The OpAmp is configured with feedback. - The non-inverting input (+) receives the voltage \( v_2 \) after the \(8 \, \Omega\) resistor. - The inverting input (-) is connected to \( v_1 \). **Graph/Diagram Explanation:** This circuit includes a voltage source, resistors, and an ideal OpAmp. The \(16 \, \Omega\), \(24 \, \Omega\), and \(8 \, \Omega\) resistors create a voltage divider that affects the voltage at \( v_1 \) and \( v_2 \). The OpAmp amplifies the difference between these inputs, resulting in the output voltage \( v_o \). The \(12 \, \Omega\) resistor is part of the feedback loop, influencing the gain and stability of the OpAmp. **Assumption:** The OpAmp is ideal, implying: - Infinite open-loop gain - Infinite input impedance - Zero output impedance **Objective:** Determine the value of \( v_o \).
Expert Solution
Step 1

For ideal opamp voltage across inverting terminal as well as non inverting terminal is same.

And also current entering the inverting as well as non inverting terminal is zero.

Use  KCL at node and voltage division rule to find output voltage Vo.

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