Find two solutions to each equation in the interval 0 < 0 < 2n. Make sure to use RADIAN mode. a) cos 0 = 0.15 b) tan 0-= V3 (exact answer) c) sin 0 = 0.2 cos'C.IS = 1,420. sin",2 =0.201 %3D tan teno = tan' N} 8 = 1.047 Y 7 1.0 = 4.141 こ 27-1.420= |4.862 P + C. 201 = 2.94 Find two solutions to each equation in the interval -90° < 0 < 270°. Make sure to use DEGREE mode. d) cos 0 = .766 e) tan 0 = -5 ten "(-s)= -1.373 ř +Gl,373)=1,78 f) cot 0 = 2 tano= ten-()=C 463 Y + C.463. =3.604 Cas (766)= ,698 2r too698= 6.981 18 sin 0 = -.31 h) sec 0 i) csc e = 6 11 Sin (-.31) = - . 315 sino = = cos'( =0,913 CCS = Y-(-.315) = 3,456 P -0.167 = 2,974 27T -0. 913 =5.370' 2. If sec 0 = -8/3 and sin 0 < 0, find the exact value of cot 0.
Find two solutions to each equation in the interval 0 < 0 < 2n. Make sure to use RADIAN mode. a) cos 0 = 0.15 b) tan 0-= V3 (exact answer) c) sin 0 = 0.2 cos'C.IS = 1,420. sin",2 =0.201 %3D tan teno = tan' N} 8 = 1.047 Y 7 1.0 = 4.141 こ 27-1.420= |4.862 P + C. 201 = 2.94 Find two solutions to each equation in the interval -90° < 0 < 270°. Make sure to use DEGREE mode. d) cos 0 = .766 e) tan 0 = -5 ten "(-s)= -1.373 ř +Gl,373)=1,78 f) cot 0 = 2 tano= ten-()=C 463 Y + C.463. =3.604 Cas (766)= ,698 2r too698= 6.981 18 sin 0 = -.31 h) sec 0 i) csc e = 6 11 Sin (-.31) = - . 315 sino = = cos'( =0,913 CCS = Y-(-.315) = 3,456 P -0.167 = 2,974 27T -0. 913 =5.370' 2. If sec 0 = -8/3 and sin 0 < 0, find the exact value of cot 0.
Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE:
1. Give the measures of the complement and the supplement of an angle measuring 35°.
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Can you check if these are right please
Transcribed Image Text:Find two solutions to each equation in the interval 0 < 0 < 2r. Make sure to use RADIAN mode.
a) cos 0 = 0.15
(exact answer) c) sin 0 = 0.2
-1
b) tan 0-=
V3
Cos'C15 = 1,420.
sin,2 =r0201
ニ
tan teno = ten'N}
,8 = 1.047
27-1.420=|4.862
N+ C. 20 1 = 2.94
こ
Y i 1.0 = 4.141
Find two solutions to each equation in the interval -90° < 0 < 270°. Make sure to use DEGREE mode.
e) tan 0 = -5
ten (-s) = -1.373
ř +(1,373)=1,78
f) cot 0 = 2
tano=
ten'()=C463
d) cos 0 = .766
Ccs (766): ,698
!!
つT.(99 - 6.981
Y+ C.463.=3.604
18
h) sec 0 =
11
i)
csc 0 = 6
sin 0 = -.31
Sin (. 31) = - 315
sino = Ź
こ
Y-(-.315) = 3.456
`cos' () =0,913
sin' (i)=167
P-0.167 = 2.974
0.413=5.370
2.
If sec 0 = -8/3 and sin 0 < 0, find the exact value of cot 0.
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