Find two power series solutions of the given differential equation about the ordinary point x = 0. y" + 8xy' + 8y = 0 Oy₁ = 1 - 4x²8x4 32 6 3 Oy₁ = 1 - 4x² + 8x4 - 32x6. 32 6 Oy₁ = 1 + 4x² - 8x4 + -x +... and y₂ = x - 3 Oy₁ = 1 - 4x² - 8x4 - -32x6 and Y₂ = X- Oy₁ = 1 - 4x² + 8x4 - 32 x6 - 3 + ... and y₂ = x- and y₂ = x + and y₂ = x + 83 64 5 + -X 15 00 m 8 -X + 3 8 3 8 8.3 3 64 5 + 15 + 64.5 -X + 15 64 5 -X 15 64 5 -X 15 + + 512 7 105 512 7 105 512 7 105 512 -X 105 512 7 105 + +... +... + -X + ***

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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**Power Series Solutions for Differential Equations**

**Problem Statement:**
Find two power series solutions of the given differential equation about the ordinary point \( x = 0 \).

\[ y'' + 8xy' + 8y = 0 \]

**Solution Options:**

1. \[
   \mathbf{y_1 = 1 - 4x^2 + 8x^4 - \frac{32}{3}x^6 - \cdots} \quad \text{and} \quad 
   \mathbf{y_2 = x - \frac{8}{3}x^3 + \frac{64}{15}x^5 - \frac{512}{105}x^7 + \cdots}
   \]

2. \[
   \mathbf{y_1 = 1 + 4x^2 + 8x^4 + \frac{32}{3}x^6 + \cdots} \quad \text{and} \quad 
   \mathbf{y_2 = x - \frac{8}{3}x^3 + \frac{64}{15}x^5 - \frac{512}{105}x^7 + \cdots}
   \]

3. \[
   \mathbf{y_1 = 1 - 4x^2 + 8x^4 - \frac{32}{3}x^6 - \cdots} \quad \text{and} \quad 
   \mathbf{y_2 = x + \frac{8}{3}x^3 + \frac{64}{15}x^5 + \frac{512}{105}x^7 + \cdots}
   \]

4. \[
   \mathbf{y_1 = 1 - 4x^2 + 8x^4 - \frac{32}{3}x^6 - \cdots} \quad \text{and} \quad 
   \mathbf{y_2 = x - \frac{8}{3}x^3 + \frac{64}{15}x^5 - \frac{512}{105}x^7 + \cdots}
   \]

5. \[
   \mathbf{y_1 = 1 - 4x^2 + 8x^4 - \frac{32}{3}
Transcribed Image Text:--- **Power Series Solutions for Differential Equations** **Problem Statement:** Find two power series solutions of the given differential equation about the ordinary point \( x = 0 \). \[ y'' + 8xy' + 8y = 0 \] **Solution Options:** 1. \[ \mathbf{y_1 = 1 - 4x^2 + 8x^4 - \frac{32}{3}x^6 - \cdots} \quad \text{and} \quad \mathbf{y_2 = x - \frac{8}{3}x^3 + \frac{64}{15}x^5 - \frac{512}{105}x^7 + \cdots} \] 2. \[ \mathbf{y_1 = 1 + 4x^2 + 8x^4 + \frac{32}{3}x^6 + \cdots} \quad \text{and} \quad \mathbf{y_2 = x - \frac{8}{3}x^3 + \frac{64}{15}x^5 - \frac{512}{105}x^7 + \cdots} \] 3. \[ \mathbf{y_1 = 1 - 4x^2 + 8x^4 - \frac{32}{3}x^6 - \cdots} \quad \text{and} \quad \mathbf{y_2 = x + \frac{8}{3}x^3 + \frac{64}{15}x^5 + \frac{512}{105}x^7 + \cdots} \] 4. \[ \mathbf{y_1 = 1 - 4x^2 + 8x^4 - \frac{32}{3}x^6 - \cdots} \quad \text{and} \quad \mathbf{y_2 = x - \frac{8}{3}x^3 + \frac{64}{15}x^5 - \frac{512}{105}x^7 + \cdots} \] 5. \[ \mathbf{y_1 = 1 - 4x^2 + 8x^4 - \frac{32}{3}
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