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- 6.2 The Standard Normal Distribution Table: Z-score and Probability A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 164.7 cm and a standard deviation of 2.5 cm. Find the probability that the length of a randomly selected steel rod is greater than 167.7 cm. Probability -Suppose X has a normal distribution with mean 135 and variance 36. Find the 67th percentile of the distribution of X. Answer choice 132.36 137.64 146.76 123.24On average, a banana will last 6.1 days from the time it is purchased in the store to the time it is too rotten to eat. Is the mean time to spoil greater if the banana is hung from the ceiling? The data show results of an experiment with 13 bananas that are hung from the ceiling. Assume that that distribution of the population is normal. 7.4, 7.5, 7.9, 5.7, 5.9, 8.1, 4.8, 8.7, 6.8, 5.9, 8.2, 5.1, 5.1 What can be concluded at the the αα = 0.10 level of significance level of significance? For this study, we should use Correct The alternative hypothesis would be: H1:H1: Correct Correct Correct The test statistic Correct = (please show your answer to 3 decimal places.) Based on this, we should Correct the null hypothesis. Thus, the final conclusion is that ...
- Assume the samples are random and independent, the populations are nomally distributed, and the population variances are equal. The table available below shows the prices (in dollars) for a sample of automobile batteries. The prices are classified according to battery type. At a = 0.10, is there enough evidence conclude that at least one mean battery price is different from the others? Complete parts (a) through (e) below. E Click the icon to view the battery cost data. (a) Let u1. P2. H3 represent the mean prices for the group size 35, 65, and 24/24F respectively. Identify the claim and state Ho and H. H Cost of batteries by type The claim is the V hypothesis. Group size 35 Group size 65 Group size 24/24F 101 111 121 124 D 146 173 182 278 124 140 141 89 (b) Find the critical value, Fo, and identify the rejection region. 90 79 84 The rejection region is F Fo, where Fo = (Round to two decimal places as needed.) (c) Find the test statistic F. Print Done F= (Round to two decimal places as…Use the magnitudes (Richter scale) of the 120 earthquakes listed in the accompanying data table. Use technology to find the range, variance, and standard deviation. If another value, 8.00, is added to those listed in the data set, do the measures of variation change much? 3.272.452.542.432.752.372.192.421.911.432.851.731.992.322.332.704.742.873.382.722.833.423.952.993.873.473.082.942.703.602.842.373.033.232.593.643.242.662.352.432.813.952.522.922.983.412.272.562.933.162.201.151.934.002.542.832.352.311.522.801.951.602.452.332.081.553.201.491.812.551.662.352.452.082.192.752.002.792.392.671.692.881.841.991.862.561.972.183.671.553.162.461.881.502.793.283.822.752.452.712.541.642.183.032.361.481.922.322.651.411.391.802.242.302.481.732.402.442.482.44Use sample standard deviation formula to find the standard deviation of these BMI’s: 33.3, 28, 45.4, 28.4 and 25.9.
- A bank's loan officer rates applicants for credit. The ratings are normally distributed with a mean of 200 and a standard deviation of 50. If 64 applications are randomly selected, what is the probability that the mean credit rating of these 64 applicants will be between 205 and 275. (Round your answer to 4 decimal places.) (Calculator: http://statisticshelper.com/normal-distribution-calculator) A. 0.5011 B. 0.4113 C. 0.2119 D. 0.3664Find the F-test statistic to test the claim that the variances of the two populations are equal. Both distributions are normal. The populations are independent. The standard deviation of the first sample is 6.5752 7.3865 is the standard deviation of the second sample.This assignment is worth 1 points. The extra point will be added to your overall course grade. For example: if you receive an 88% in the course you can receive up to 1 point giving you a new score of 89%. The following rubric will be used. 0.25 point for drawing the normal distribution curve with the mean value labeled on the curve and the appropriate area shaded. 0.25 point for determining the value of the standard deviation of the sample mean. 0.5 point for finding the correct probability. All work must be shown in order to receive any credit. Please upload your completed assignment here. The length of time taken on the SAT for a group of students is normally distributed with a mean of 2.5 hours and a standard deviation of 0.25 hours. A sample size of n = 60 is drawn randomly from the population. Find the probability that the sample mean is between two hours and three hours.
- Suppose in a large class, students' grades in a test followed the normal distribution. Approximately what percent of grades are between two standard deviations below the mean and two standard deviations above the mean? (that is in between Xbar-2S and Xbar+2S grades). Note, Xbar is the mean, and S is the standard deviation. 34.3 47.9 95.8Calculate the standard deviation and variance of the given random sample data. Round to two decimal places. x 6.9 3.2 29.9 20.7 27 13.6 PART A: WHAT IS THE Standard deviation: PART B : WHAT IS THE VarianceOn average, a banana will last 6.1 days from the time it is purchased in the store to the time it is too rotten to eat. Is the mean time to spoil greater if the banana is hung from the ceiling? The data show results of an experiment with 12 bananas that are hung from the ceiling. Assume that that distribution of the population is normal. 5.5, 6.6, 5.1, 8.4, 7.1, 5.1, 4.8, 5.1, 8.1, 5.4, 7, 7.8 What can be concluded at the the a = 0.05 level of significance level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Ho: ? Select an answer ✓ H₁: ? Select an answer ✓ 4 c. The test statistic?v= (please show your answer to 3 decimal places.) (Please show your answer to 4 decimal places.) d. The p-value =
