Find the z-score given the cumulative probabilities, mean and standard deviation in brackets a) NORMINV(0.99,490,61) b) NORMSINV(0.99)
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Q: A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of…
A: Given that, A company produces steel rods. The lengths of the steel rods are normally distributed…
Q: A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of…
A:
Q: company produces steel rods. The lengths of the steel rods are normally distributed with a mean of…
A:
Q: A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of…
A:
Q: A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of…
A: The random variable length of the steel rods follows normal distribution. The population mean is…
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Q: A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of…
A:
Q: A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of…
A: It is given that the mean is 224.2, the standard deviation is 1.2 and the sample size is 22.
Q: P(M> 113.4-cm) = %3D
A:
Q: A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of…
A: Solution: Let X be the length of the steel rod. From the given information, X follows normal…
Q: A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of…
A: Given : mean = μ = 206.7 standard deviation = σ= 1.5 n = 9 μM = 206.7 σM=σn σM=1.59 σM=0.5
Q: A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of…
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Q: 2) IQ scores are normally distributed with mean 100 and standard deviation 16. a) Calculate the…
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Q: A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of…
A: Given information: The distribution is normal. μ=183.6σ=2.5n=19 P(M>182.8)=?
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Q: A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of…
A:
Q: A company produces steel rods. The lengths of the steel rods are normally distributed with a mea of…
A:
Q: A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of…
A: The lengths of the steel rods are normally distributed with a mean of 148.4-cm and a standard…
Q: ounts of time per workout an athlete uses a stairclimber are normally distributed, with a mean of 21…
A: It is given that Mean = 21Standard deviation = 5
Q: A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of…
A: Let X denote the length of steel rod with a mean μ=110.3 cmand standard deviation σ=2 cm.X follows…
Q: A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of…
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Q: A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of…
A: Step 1:Step 2: Step 3: Step 4:
Q: company produces steel rods. The lengths of the steel rods are normally distributed with a mean of…
A: We have given that X~N(mu , sigma) mu=260.7 , sigma =1.4 , n = 25 Z-score = (x -…
Q: The amounts of time per workout an athlete uses a stairclimber are normally distributed, with a mean…
A: Step 1: State the given information.Data are normally distributed.Mean, μ: 21 minutesStandard…
Q: A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of…
A:
Q: A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of…
A: Given information Mean µ = 96.1 cm Standard deviation σ = 1.1 cm n = 30
Q: A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of…
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Q: A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of…
A: Given that, μ=258.5,σ=2.3n=30 The probability that a average length of a randomly selected bundle…
Q: A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of…
A: Solution: Let X be the length of the steel rod. From the given information, X follows normal…
Q: A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of…
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Q: A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of…
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Find the z-score given the cumulative
a) NORMINV(0.99,490,61)
b) NORMSINV(0.99)
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- A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 177.1-cm and a standard deviation of 1.2-cm. For shipment, 8 steel rods are bundled together.Find the probability that the average length of a randomly selected bundle of steel rods is greater than 177.4-cm.P(M > 177.4-cm) = Enter your answer as a number accurate to 4 decimal places. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 111.7-cm and a standard deviation of 1.4-cm. For shipment, 7 steel rods are bundled together.Find the probability that the average length of a randomly selected bundle of steel rods is between 111.5-cm and 112-cm.P(111.5-cm < M < 112-cm) = Enter your answer as a number accurate to 4 decimal places. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.The amounts of time per workout an athlete uses a stairclimber are normally distributed, with a mean of 21 minutes and a standard deviation of 6 minutes. Find the probability that a randomly selected athlete uses a stairclimber for (a) less than 17 minutes, (b) between 21 and 28 minutes, and (c) more than 30 minutes. (a) The probability that a randomly selected athlete uses a stairclimber for less than 17 minutes is (Round to four decimal places as needed.) (b) The probability that a randomly selected athlete uses a stairclimber between 21 and 28 minutes is (Round to four decimal places as needed.) (c) The probability that a randomly selected athlete uses a stairclimber for more than 30 minutes is (Round to four decimal places as needed.)
- The average electricity bill for residents of Seaside is $72.54 with a standard deviation of $9.66. Assume the population of electricity bill amounts are normally distributed. What is the probability that a randomly selected electricity bill for a resident of Seaside will be between $60 and $80? Show how you calculated your result here (type in what you typed on your calculator or computer, the function used on the calculator/computer with value input, etc) Calculation: ____________ Now type in your final simplified or rounded answer, if necessary round your answer to four decimal places. P( $60 < x < $80 ) = _____________A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 254.8-cm and a standard deviation of 1.3-cm. For shipment, 8 steel rods are bundled together. Find the probability that the average length of a randomly selected bundle of steel rods is between 253.9-cm and 254-cm. P(253.9-cm < M < 254-cm) = Enter your answer as a number accurate to 4 decimal places. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.The ages of students in an evening stained glass making class at a community college are normally distributed with a mean of 28 years and a standard deviation of 3.5 years. Determine the probability that a randomly selected student in this class is between the ages of 23 and 30. 17. (3)
- A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 148.4-cm and a standard deviation of 2.3-cm. For shipment, 16 steel rods are bundled together.Find the probability that the average length of a randomly selected bundle of steel rods is greater than 148.9-cm.P(M > 148.9-cm) = Enter your answer as a number accurate to 4 decimal places. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 225.1- cm and a standard deviation of 0.6-cm. For shipment, 18 steel rods are bundled together. Find the probability that the average length of a randomly selected bundle of steel rods is greater than 224.9-cm. P(M> 224.9-cm) = Enter your answer as a number accurate to 4 decimal places. Answers obtained using exact z-scores or z- scores rounded to 3 decimal places are accepted.A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 249.5-cm and a standard deviation of 2.1-cm. For shipment, 11 steel rods are bundled together.Find the probability that the average length of a randomly selected bundle of steel rods is between 250.6-cm and 251.5-cm.P(250.6-cm < M < 251.5-cm) = Enter your answer as a number accurate to 4 decimal places. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.
- A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 163.9-cm and a standard deviation of 1.6-cm. For shipment, 20 steel rods are bundled together.Find the probability that the average length of a randomly selected bundle of steel rods is between 163.3-cm and 165-cm.PP(163.3-cm < ¯xx¯ < 165-cm) = Enter your answer as a number accurate to 4 decimal places.A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 269.6-cm and a standard deviation of 2.1-cm. For shipment, 8 steel rods are bundled together. Find the probability that the average length of a randomly selected bundle of steel rods is between 267.9-cm and 272-cm. P(267.9-cm < M<272-cm) = Enter your answer as a number accurate to 4 decimal places. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted. Ouestion LlolnA company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 126.7-cm and a standard deviation of 2.4-cm. For shipment, 16 steel rods are bundled together.Find the probability that the average length of a randomly selected bundle of steel rods is greater than 127.4-cm.P(M > 127.4-cm) = Enter your answer as a number accurate to 4 decimal places. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.
