Find the x center of mass of the following masses at their respective coordinates: m1=1.5, x1=0.6,y1=-0.8 m2=4.0, x2=-0.8,y2=-2.8 m3=2.5, x3=-1.2,y3=-5.0 X_com=?

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### Calculating the Center of Mass in the \(x\)-Direction

To find the \(x\) center of mass (\(x_{com}\)) of the given masses at their respective coordinates, follow these steps:

Given data:

- \(m_1 = 1.5\), \(x_1 = 0.6\), \(y_1 = -0.8\)
- \(m_2 = 4.0\), \(x_2 = -0.8\), \(y_2 = -2.8\)
- \(m_3 = 2.5\), \(x_3 = -1.2\), \(y_3 = -5.0\)

The formula to find the \(x\) center of mass ( \(x_{com}\) ) is:

\[ 
x_{com} = \frac{\sum (m_i \cdot x_i)}{\sum m_i} 
\]

**Step-by-Step Calculation:**

1. Calculate the numerator of the \(x_{com}\):

\[
\sum (m_i \cdot x_i) = (m_1 \cdot x_1) + (m_2 \cdot x_2) + (m_3 \cdot x_3)
\]

\[
= (1.5 \cdot 0.6) + (4.0 \cdot -0.8) + (2.5 \cdot -1.2)
\]

\[
= 0.9 + (-3.2) + (-3.0)
\]

\[
= 0.9 - 3.2 - 3.0
\]

\[
= -5.3 
\]

2. Calculate the denominator of the \(x_{com}\):

\[
\sum m_i = m_1 + m_2 + m_3
\]

\[
= 1.5 + 4.0 + 2.5 = 8.0
\]

3. Divide the numerator by the denominator to find the \(x_{com}\):

\[
x_{com} = \frac{-5.3}{8.0} \approx -0.6625
\]

Therefore, the \(x\) center of mass (\(x_{com}\)) of the given masses is approximately \(-0.6625\).
Transcribed Image Text:### Calculating the Center of Mass in the \(x\)-Direction To find the \(x\) center of mass (\(x_{com}\)) of the given masses at their respective coordinates, follow these steps: Given data: - \(m_1 = 1.5\), \(x_1 = 0.6\), \(y_1 = -0.8\) - \(m_2 = 4.0\), \(x_2 = -0.8\), \(y_2 = -2.8\) - \(m_3 = 2.5\), \(x_3 = -1.2\), \(y_3 = -5.0\) The formula to find the \(x\) center of mass ( \(x_{com}\) ) is: \[ x_{com} = \frac{\sum (m_i \cdot x_i)}{\sum m_i} \] **Step-by-Step Calculation:** 1. Calculate the numerator of the \(x_{com}\): \[ \sum (m_i \cdot x_i) = (m_1 \cdot x_1) + (m_2 \cdot x_2) + (m_3 \cdot x_3) \] \[ = (1.5 \cdot 0.6) + (4.0 \cdot -0.8) + (2.5 \cdot -1.2) \] \[ = 0.9 + (-3.2) + (-3.0) \] \[ = 0.9 - 3.2 - 3.0 \] \[ = -5.3 \] 2. Calculate the denominator of the \(x_{com}\): \[ \sum m_i = m_1 + m_2 + m_3 \] \[ = 1.5 + 4.0 + 2.5 = 8.0 \] 3. Divide the numerator by the denominator to find the \(x_{com}\): \[ x_{com} = \frac{-5.3}{8.0} \approx -0.6625 \] Therefore, the \(x\) center of mass (\(x_{com}\)) of the given masses is approximately \(-0.6625\).
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