Physics for Scientists and Engineers, Technology Update (No access codes included)
9th Edition
ISBN:9781305116399
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter7: Energy Of A System
Section: Chapter Questions
Problem 7.44P: (a) Suppose a constant force acts on an object. The force does not vary with time or with the...
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![### Exercise 1: Calculating Work Done
**Problem:** Find the work done when lifting a 45 lb crate from the ground up onto a 7 ft high shelf.
**Solution:**
To find the work done in lifting the crate, you can use the formula for work in the context of lifting objects against gravity:
\[ \text{Work} = \text{Force} \times \text{Distance} \]
1. **Determine the force:**
The force in this case is equivalent to the weight of the crate. Given that the crate weighs 45 lbs, the force \( F \) is 45 lbs.
2. **Determine the distance:**
The distance \( d \) the crate is lifted is 7 feet.
3. **Calculate the work:**
Plug in the values into the formula:
\[
\text{Work} = 45 \, \text{lbs} \times 7 \, \text{ft} = 315 \, \text{foot-pounds}
\]
So, the work done to lift the crate onto the shelf is **315 foot-pounds**.
There are no graphs or diagrams accompanying this problem. The calculation is straightforward and solely involves using the above formula.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6a885dd9-3ed1-489d-bae2-5a33154ef1ff%2F0f1b6d86-0be4-417f-bbd1-911ca7d9bde0%2F9q48cb6_processed.png&w=3840&q=75)
Transcribed Image Text:### Exercise 1: Calculating Work Done
**Problem:** Find the work done when lifting a 45 lb crate from the ground up onto a 7 ft high shelf.
**Solution:**
To find the work done in lifting the crate, you can use the formula for work in the context of lifting objects against gravity:
\[ \text{Work} = \text{Force} \times \text{Distance} \]
1. **Determine the force:**
The force in this case is equivalent to the weight of the crate. Given that the crate weighs 45 lbs, the force \( F \) is 45 lbs.
2. **Determine the distance:**
The distance \( d \) the crate is lifted is 7 feet.
3. **Calculate the work:**
Plug in the values into the formula:
\[
\text{Work} = 45 \, \text{lbs} \times 7 \, \text{ft} = 315 \, \text{foot-pounds}
\]
So, the work done to lift the crate onto the shelf is **315 foot-pounds**.
There are no graphs or diagrams accompanying this problem. The calculation is straightforward and solely involves using the above formula.
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