Find the volume of the solid. Round your answer to the nearest tenth or write in terms of pi. Hint: Volume of a cylinder: V = Bh, Volume of a sphere: V = 4/3TTP 15. r = 5 in, h = 8 in 16. r = 6 cm

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ChapterP: Prerequisites: Fundamental Concepts Of Algebra
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Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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find the volume of the solid. Round the answer to the nearest tenth or write in terms of pi. See image attached.
### Calculating the Volume of Solids

**Objective:** Determine the volume of the given solid shapes. Round your answer to the nearest tenth or express the answer in terms of π.

**Equations:**

- **Volume of a Cylinder:** \( V = Bh \)
- **Volume of a Sphere:** \( V = \frac{4}{3} \pi r^3 \)

where:
- \( B \) is the area of the base of the cylinder (\( B = \pi r^2 \))
- \( h \) is the height of the cylinder
- \( r \) is the radius of the base or the radius of the sphere.

**Examples:**

**15. Volume of a Cylinder**
- **Given:**
  - Radius (\( r \)) = 5 inches
  - Height (\( h \)) = 8 inches
  
- **Calculation:**
  1. Find the area of the base \( B \):
     \[
     B = \pi r^2 = \pi (5)^2 = 25\pi \text{ square inches}
     \]
  2. Calculate the Volume \( V \):
     \[
     V = Bh = 25\pi \times 8 = 200\pi \text{ cubic inches} \approx 628.3 \text{ cubic inches}
     \]

- **Diagram:**
  - A blue cylinder with a radius of 5 inches and a height of 8 inches.

**16. Volume of a Sphere**
- **Given:**
  - Radius (\( r \)) = 6 cm
  
- **Calculation:**
  1. Calculate the volume \( V \):
     \[
     V = \frac{4}{3} \pi r^3 = \frac{4}{3} \pi (6)^3 = \frac{4}{3} \pi (216) = 288\pi \text{ cubic centimeters} \approx 904.8 \text{ cubic centimeters}
     \]

- **Diagram:**
  - A green sphere with a radius of 6 cm.

By understanding and applying these volume formulas, students can efficiently solve problems related to the volume of cylinders and spheres.
Transcribed Image Text:### Calculating the Volume of Solids **Objective:** Determine the volume of the given solid shapes. Round your answer to the nearest tenth or express the answer in terms of π. **Equations:** - **Volume of a Cylinder:** \( V = Bh \) - **Volume of a Sphere:** \( V = \frac{4}{3} \pi r^3 \) where: - \( B \) is the area of the base of the cylinder (\( B = \pi r^2 \)) - \( h \) is the height of the cylinder - \( r \) is the radius of the base or the radius of the sphere. **Examples:** **15. Volume of a Cylinder** - **Given:** - Radius (\( r \)) = 5 inches - Height (\( h \)) = 8 inches - **Calculation:** 1. Find the area of the base \( B \): \[ B = \pi r^2 = \pi (5)^2 = 25\pi \text{ square inches} \] 2. Calculate the Volume \( V \): \[ V = Bh = 25\pi \times 8 = 200\pi \text{ cubic inches} \approx 628.3 \text{ cubic inches} \] - **Diagram:** - A blue cylinder with a radius of 5 inches and a height of 8 inches. **16. Volume of a Sphere** - **Given:** - Radius (\( r \)) = 6 cm - **Calculation:** 1. Calculate the volume \( V \): \[ V = \frac{4}{3} \pi r^3 = \frac{4}{3} \pi (6)^3 = \frac{4}{3} \pi (216) = 288\pi \text{ cubic centimeters} \approx 904.8 \text{ cubic centimeters} \] - **Diagram:** - A green sphere with a radius of 6 cm. By understanding and applying these volume formulas, students can efficiently solve problems related to the volume of cylinders and spheres.
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