Find the volume of the solid generated by revolving the region bounded by the graphs of the equations about the x-axis. y = e-5x y = 0 x = 0 X = 3

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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To find the volume of the solid generated by revolving the region bounded by the given graphs about the x-axis, follow these steps.

The equations defining the region are:
\[ y = e^{-5x} \]
\[ y = 0 \]
\[ x = 0 \]
\[ x = 3 \]

**Explanation:**
We need to find the volume of the solid formed when this region is revolved about the x-axis. This type of volume calculation can be done using the method of disks or washers.

**Steps:**

1. **Identify the function and bounds:**
   The function \( y = e^{-5x} \) is bounded by \( x = 0 \) and \( x = 3 \), and the line \( y = 0 \) forms the lower boundary.

2. **Setup the Disk Method Integral:**
   When revolving around the x-axis, the radius of a cylindrical disk at a point \( x \) is given by the function \( y = e^{-5x} \). The volume of each disk is \( \pi \cdot [radius]^2 \cdot [thickness] \). Hence, we need to integrate the area of these disks from \( x = 0 \) to \( x = 3 \).

3. **Write the Volume Integral:**
   \[
   V = \pi \int_{0}^{3} (e^{-5x})^2 \, dx
   \]

4. **Simplify the Integrand:**
   Simplify the expression inside the integral:
   \[
   V = \pi \int_{0}^{3} e^{-10x} \, dx
   \]

5. **Evaluate the Integral:**
   To integrate \( e^{-10x} \), we use the formula for the integral of the exponential function:
   \[
   \int e^{ax} \, dx = \frac{1}{a} e^{ax} + C
   \]
   Substituting \( a = -10 \):
   \[
   \int e^{-10x} \, dx = -\frac{1}{10} e^{-10x} + C
   \]

6. **Apply the Bounds:**
   Evaluate the definite integral from \( 0 \) to \( 3 \):
   \[
   V = \pi \left[ -\frac{1}{10} e
Transcribed Image Text:To find the volume of the solid generated by revolving the region bounded by the given graphs about the x-axis, follow these steps. The equations defining the region are: \[ y = e^{-5x} \] \[ y = 0 \] \[ x = 0 \] \[ x = 3 \] **Explanation:** We need to find the volume of the solid formed when this region is revolved about the x-axis. This type of volume calculation can be done using the method of disks or washers. **Steps:** 1. **Identify the function and bounds:** The function \( y = e^{-5x} \) is bounded by \( x = 0 \) and \( x = 3 \), and the line \( y = 0 \) forms the lower boundary. 2. **Setup the Disk Method Integral:** When revolving around the x-axis, the radius of a cylindrical disk at a point \( x \) is given by the function \( y = e^{-5x} \). The volume of each disk is \( \pi \cdot [radius]^2 \cdot [thickness] \). Hence, we need to integrate the area of these disks from \( x = 0 \) to \( x = 3 \). 3. **Write the Volume Integral:** \[ V = \pi \int_{0}^{3} (e^{-5x})^2 \, dx \] 4. **Simplify the Integrand:** Simplify the expression inside the integral: \[ V = \pi \int_{0}^{3} e^{-10x} \, dx \] 5. **Evaluate the Integral:** To integrate \( e^{-10x} \), we use the formula for the integral of the exponential function: \[ \int e^{ax} \, dx = \frac{1}{a} e^{ax} + C \] Substituting \( a = -10 \): \[ \int e^{-10x} \, dx = -\frac{1}{10} e^{-10x} + C \] 6. **Apply the Bounds:** Evaluate the definite integral from \( 0 \) to \( 3 \): \[ V = \pi \left[ -\frac{1}{10} e
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