Find the volume of the shaded solid. Round your answer to 2 decimal places if necessary. Use a = 3.14 when necessary. O A. 440.32 m3 O B. 4,382.72 m3 OC. 1,607.68 m3 OD. 2,048.00 m³ Sm 32 m 8 m

Algebra and Trigonometry (6th Edition)
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ChapterP: Prerequisites: Fundamental Concepts Of Algebra
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Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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### Problem Statement:

Find the volume of the shaded solid. Round your answer to 2 decimal places if necessary. Use \( \pi = 3.14 \) when necessary.

### Diagram Description:

The provided diagram illustrates a cylinder placed inside a rectangular prism. The dimensions of the cylinder and rectangular prism are as follows:
- The diameter of the cylinder is 8 meters.
- The height (or length) of the cylinder is 32 meters.
- The base of the rectangular prism is a square with each side measuring 8 meters.
- The height (or length) of the rectangular prism is also 32 meters, matching the cylinder.

### Solution Options:

A) \( 440.32 \, \text{m}^3 \)

B) \( 4,382.72 \, \text{m}^3 \)

C) \( 1,607.68 \, \text{m}^3 \)

D) \( 2,048.00 \, \text{m}^3 \)

### Explanation:

To find the volume of the shaded solid (the cylinder), we use the formula for the volume of a cylinder:

\[ V = \pi r^2 h \]

where:
- \( V \) is the volume
- \( \pi \) is Pi, approximately 3.14
- \( r \) is the radius of the cylinder
- \( h \) is the height of the cylinder

Given:
- Diameter = 8 meters, hence Radius (\( r \)) = \(\frac{8}{2}\) = 4 meters
- Height (\( h \)) = 32 meters

Substituting the values into the formula:

\[ V = 3.14 \times (4)^2 \times 32 \]
\[ V = 3.14 \times 16 \times 32 \]
\[ V = 3.14 \times 512 \]
\[ V = 1,607.68 \, \text{m}^3 \]

So, the correct answer is:

C) \( 1,607.68 \, \text{m}^3 \)
Transcribed Image Text:### Problem Statement: Find the volume of the shaded solid. Round your answer to 2 decimal places if necessary. Use \( \pi = 3.14 \) when necessary. ### Diagram Description: The provided diagram illustrates a cylinder placed inside a rectangular prism. The dimensions of the cylinder and rectangular prism are as follows: - The diameter of the cylinder is 8 meters. - The height (or length) of the cylinder is 32 meters. - The base of the rectangular prism is a square with each side measuring 8 meters. - The height (or length) of the rectangular prism is also 32 meters, matching the cylinder. ### Solution Options: A) \( 440.32 \, \text{m}^3 \) B) \( 4,382.72 \, \text{m}^3 \) C) \( 1,607.68 \, \text{m}^3 \) D) \( 2,048.00 \, \text{m}^3 \) ### Explanation: To find the volume of the shaded solid (the cylinder), we use the formula for the volume of a cylinder: \[ V = \pi r^2 h \] where: - \( V \) is the volume - \( \pi \) is Pi, approximately 3.14 - \( r \) is the radius of the cylinder - \( h \) is the height of the cylinder Given: - Diameter = 8 meters, hence Radius (\( r \)) = \(\frac{8}{2}\) = 4 meters - Height (\( h \)) = 32 meters Substituting the values into the formula: \[ V = 3.14 \times (4)^2 \times 32 \] \[ V = 3.14 \times 16 \times 32 \] \[ V = 3.14 \times 512 \] \[ V = 1,607.68 \, \text{m}^3 \] So, the correct answer is: C) \( 1,607.68 \, \text{m}^3 \)
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