Find the voltage needed for the electrolysis of NiBr2(aq).
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Question
Find the voltage needed for the electrolysis of NiBr2(aq).
![Table 18.1
Standard Potentials in Water Solution at 25°C
Acidic Solution, [H*] = 1 M
Li"(agi + e
K*(ag) + e
Ba (agl + 20
Ca?*(agl + 20
Na *(ag) + o
Mg (adt + 2e
AP*(ag) + 3e"
Mr?*(aql + 2e
Zn?*(aq} + 2e
C*laq\ + 3e
Fe (ag + 2e
Cr*laq\ + e
-3.040
-2936
-2.906
-2.869
Bals)
Cals)
→ Nals)
Mgls)
A(s)
-2714
-2.357
-1.68
-1.182
► Zn(s)
-0.762
-0.744
-0.409
Fels
-0.408
-0.402
PbSOds) + 20
TI'lad +e
Co?*(agl + 2e
NP*(agi + 2e
Ag(s) + e¯
Sn (ag + 20
Po (agl + 2e
2H (ag) + 2e
AgBr{s) + e¯
S(s) + 2H*(ag) + 2e
Sn*(ad + 20
SO2-ladi + 4H*(ad + 20
Cu*(ad + e
Cu²*lad + 2e
Cu*(ag\ + e
Us) + 20
Fe"(ad + e
Hg*(ag) + 2e
Ag*(ag) + o
Pbls) + SOF-(aql
-0.356
-0.336
-0 282
-0 236
-0.152
Co(s)
→ Ag(s) + I"(adt
Sni s
-0.141
P(s)
-0.127
0.000
Agls) + Br"[ag]
0.073
0.144
0.154
0.155
SO + 2H,0
Cu*lag
0.161
0.339
0.518
0.534
Fe*{ag
0.769
0.796
0.799
0 908
0.964
Agls)
NO,"(ag + 4H*(agl + 30
AuCL"lad) + 3e¬
Br + 20
O,al + 4H*lad + 46
Mn0As) + 4H*(aql + 20"
Cr;0,7~(aq) + 14H*[ag) + 6e
CAol + 20
CIO,"(aq) + 6H*(ag) + 5e"
Au*(aql + 30¯
Mn0,"lag] + 8H*(ad + 5e
PBO$) + SO2"lag] + 4H°(ag\ + 2e
H,0/ad + 2H*lag + 2e
Co*(ag +e
FAGl + 20
NO + 2H,0
► Au(s) + 4CI¯(aq\
28r (ag
2H,0
Mn*(ag + 2H,0
→20*(ag) + 7H;0
→201"(ad
1.001
1.077
1.229
1.229
1.33
1.360
1.458
→ Au(s)
→Mr*(ag) + 4H,0
→ PBSO&$) + 2H;0
2H,0
1.498
1.512
1.687
1.763
1.953
2.889
Bas e Solution, [OH¯] = 1 M
Fe(OHs) + 2e
2H,0 + 2e"
Fe(OHYS) + e
S[s) + 2e
NO,"(ag + 2H,0 + 30
NO,"(ag + H0 + 2e
CIO,"(aq) + H,0 + 20
Odel + 2H,0 + 4e"
CIO,"(ac) + 3H,0 + 6e"
CIO-(ag) + H,0 + 20
Fols) + 20H-(ag)
Hgl + 20H"{aq)
Fe(OH{s + OH"(agl
-0.891
-0 828
-0.547
-0.445
-0.140
Lie
→ NOld + 40H (ag
NO;"(adt + 20H"{ag)
CIO,"ladi + 20H-[ag)
4OH-(ad
m
0.004
0.398
0.401
CI-(aq\ + 60H¯(ad
► CI-{aq} + 20H¯(ad
0.614
0.890
Increasing strength of reducing agents
Increasing strength of oxldizing agents](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F31b9d22a-9758-43bf-9848-11a7d91a11cd%2F97483317-d065-4332-bb10-f09e1b4552da%2Fscraaa_processed.png&w=3840&q=75)
Transcribed Image Text:Table 18.1
Standard Potentials in Water Solution at 25°C
Acidic Solution, [H*] = 1 M
Li"(agi + e
K*(ag) + e
Ba (agl + 20
Ca?*(agl + 20
Na *(ag) + o
Mg (adt + 2e
AP*(ag) + 3e"
Mr?*(aql + 2e
Zn?*(aq} + 2e
C*laq\ + 3e
Fe (ag + 2e
Cr*laq\ + e
-3.040
-2936
-2.906
-2.869
Bals)
Cals)
→ Nals)
Mgls)
A(s)
-2714
-2.357
-1.68
-1.182
► Zn(s)
-0.762
-0.744
-0.409
Fels
-0.408
-0.402
PbSOds) + 20
TI'lad +e
Co?*(agl + 2e
NP*(agi + 2e
Ag(s) + e¯
Sn (ag + 20
Po (agl + 2e
2H (ag) + 2e
AgBr{s) + e¯
S(s) + 2H*(ag) + 2e
Sn*(ad + 20
SO2-ladi + 4H*(ad + 20
Cu*(ad + e
Cu²*lad + 2e
Cu*(ag\ + e
Us) + 20
Fe"(ad + e
Hg*(ag) + 2e
Ag*(ag) + o
Pbls) + SOF-(aql
-0.356
-0.336
-0 282
-0 236
-0.152
Co(s)
→ Ag(s) + I"(adt
Sni s
-0.141
P(s)
-0.127
0.000
Agls) + Br"[ag]
0.073
0.144
0.154
0.155
SO + 2H,0
Cu*lag
0.161
0.339
0.518
0.534
Fe*{ag
0.769
0.796
0.799
0 908
0.964
Agls)
NO,"(ag + 4H*(agl + 30
AuCL"lad) + 3e¬
Br + 20
O,al + 4H*lad + 46
Mn0As) + 4H*(aql + 20"
Cr;0,7~(aq) + 14H*[ag) + 6e
CAol + 20
CIO,"(aq) + 6H*(ag) + 5e"
Au*(aql + 30¯
Mn0,"lag] + 8H*(ad + 5e
PBO$) + SO2"lag] + 4H°(ag\ + 2e
H,0/ad + 2H*lag + 2e
Co*(ag +e
FAGl + 20
NO + 2H,0
► Au(s) + 4CI¯(aq\
28r (ag
2H,0
Mn*(ag + 2H,0
→20*(ag) + 7H;0
→201"(ad
1.001
1.077
1.229
1.229
1.33
1.360
1.458
→ Au(s)
→Mr*(ag) + 4H,0
→ PBSO&$) + 2H;0
2H,0
1.498
1.512
1.687
1.763
1.953
2.889
Bas e Solution, [OH¯] = 1 M
Fe(OHs) + 2e
2H,0 + 2e"
Fe(OHYS) + e
S[s) + 2e
NO,"(ag + 2H,0 + 30
NO,"(ag + H0 + 2e
CIO,"(aq) + H,0 + 20
Odel + 2H,0 + 4e"
CIO,"(ac) + 3H,0 + 6e"
CIO-(ag) + H,0 + 20
Fols) + 20H-(ag)
Hgl + 20H"{aq)
Fe(OH{s + OH"(agl
-0.891
-0 828
-0.547
-0.445
-0.140
Lie
→ NOld + 40H (ag
NO;"(adt + 20H"{ag)
CIO,"ladi + 20H-[ag)
4OH-(ad
m
0.004
0.398
0.401
CI-(aq\ + 60H¯(ad
► CI-{aq} + 20H¯(ad
0.614
0.890
Increasing strength of reducing agents
Increasing strength of oxldizing agents
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