Find the vertex, focus, and directrix of the parabola. Then sketch the parabola. (x + ¹² ) ² = = 8(y-2) Step 1 Which of the following is the correct standard form of the equation of a parabola with a vertical axis and vertex at (h, k)? O (x - k)² = 4p(y - h), p = 0 (y - k)² = 4p(x - h), p = 0 (y - k)² = p(x - h), p = 0 (y - h)² = 4p(x - k), p = 0 (x - h)² = 4p(y - k), p = 0 directrix: y = k-p directrix: x=h-p directrix: x = k-p directrix: x=h-p directrix: y=k-p

Q: Find an equation of the parabola with vertex (4, 2) and focus (4, 6).

A: Given :              Vertex (4,2) and focus (4,6)       Since the vertex and focus have common…

Q: Use the information provided to write the equation of each parabola. Vertex: (-1,9), Focus: (-3, 9)…

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Q: Find an equation of the parabola drawn below: 2 Xx Select one: O a. (x + 2)2 = 2 (y + 2) O b.…

A: We have to find the equation of parabola.

Q: Find the standard form of the equation of the parabola with the given characteristics. Vertex:…

A: To find the standard form of the equation of the parabola with the below characteristics. Vertex:…

Q: Find the Parabola with Focus (7,-2) and Directrix x=-9

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Q: Find the axis of symmetry of the parabola x2-16 y-6 x+73 0 Select one: Oy= -8 O x= 3 Oy= 3 Ox= -3

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Q: The parabola described in the equation y = 2(x - 4)2 + 3 has the directrix at y = -1. The focus of…

A: As per the guidelines we are supposed to solve one question at a time. Please repost other questions…

Q: Find the equation of the following parabola. Express your answer in standard form. 20 -15 -10 -5 15…

A: The standard equation of the parabola is written in the form ofy=ax2+bx+c

Q: Write an equation of the parabola in vertex form. (8,3) 8 (4,-1) 4 An equation of the parabola is y…

A: Equation of parabola which open upwards or downward in the vertex form is y=a(x-h)2+k  here (h,k) is…

Q: Find an equation of the parabola drawn below: 0 Select one: 2 X a. (x-2)² = 2 (y + 2) O b. (x + 2)2…

A: We can answer the question as below.

Q: Find an equation of the parabola with focus (-9,-3) and directrix x=-1

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Q: Graph the hyperbola (y+3)2/16-(x+6)2/4=1

A: The given equation is (y+3)2/16-(x+6)2/4=1.